1 x f + 1/3 x 3f + 1/5 x 5f + 1/7 x 7f....
If f=1 kHz, isnt 3f then 3 kHz?
And since 1/3 x 3 kHz is 1 kHz, isn't then 1/3 x 3f the same as 1 x f ?
So 1 x 1f + 1 x 1f + 1 x 1f ... or just infinity f
Did i miss something?
I think what it should be is a bit more like the thing below (try typing that into v-bulletin) which holds true of all repeating signals, not just square waves (they just hapen to have much larger percentages of the higher harmonics than some other signals like sine, or triangle waves).
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Lars Clausen said:
If f=1 kHz, isnt 3f then 3 kHz?
And since 1/3 x 3 kHz is 1 kHz, isn't then 1/3 x 3f the same as 1 x f ?
So 1 x 1f + 1 x 1f + 1 x 1f ... or just infinity f
Did i miss something?
Lars, what he meant was 1A x 1f + 1/3A x 3f + 1/5A x 5f ... etc, where A = amplitude.
Who says Math cant be fun ?
Fourier Series of a Square wave
∞
x(t) = ∑ (4V/ k* pi) sin (kwt) V = amplitude
k =1
Where k is odd
So basically you get the fundamental w (angular freq) and odd harmonics decreasing at a rate of 1/k
w = 4V / pi
3w = 4V / 3pi
5w = 4V / 5pi
and so forth until finity or you stop caring
Fourier Series of a Square wave
∞
x(t) = ∑ (4V/ k* pi) sin (kwt) V = amplitude
k =1
Where k is odd
So basically you get the fundamental w (angular freq) and odd harmonics decreasing at a rate of 1/k
w = 4V / pi
3w = 4V / 3pi
5w = 4V / 5pi
and so forth until finity or you stop caring
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