I did not connect any load to the Voutput when first turned out to test it after assembled the board. I realized it after the fact and now it does not seem to work as I have anticipated and not really sure if that caused a problem. Output voltage measurement is about 46 volt which is 10 times lower than what I have in mind with 10K load connected to Vout. Output voltage is regulated at about 46V with input varied from 70V to a few hundreds volt. The weird thing is that when I increased or decreased the output load from 10K it changed output voltage a lot. In simulation using LTspice the Output voltage should be 457 volt with input of about 480 volt and more regardless of the output load. Any suggestions?
Your board are rock stable regardless input and load current variation. I have not tested out the overload current feature yet. One thing I noted to watch out for (just for reference purpose in case someone do the measurement) if one takes a voltage measurement at R11 the voltage will be impacted by the loading input impedance of the multimeter. At first I did not pay attention to it and wonder why the output dropped 28 volt (in my case) when making measurement there.
Just completed testing all features of the power supply today. Input is about 470-485V. Regulated Output is 455V with varying load from 100mA to 300mA. I also tested out the overload feature and the circuit shut downed at about 310mA as expected and turned back on after I decreased the load current and activated the momentary switch feature. It worked great.
a question:
the PCB assembly guide states the following: "To set the current limit you need to select a single resistor, R16. Current limiting occurs when the voltage across R16 reaches approximately 0.8 V. So, for example, if you want a current limit of 180 mA, your R6 will be 0.8/0.180 = 3.3 Ω."
I wonder if by any chance there is a printing error and the value of 3.3ohm refers to R16 instead of R6 as it is written?
the PCB assembly guide states the following: "To set the current limit you need to select a single resistor, R16. Current limiting occurs when the voltage across R16 reaches approximately 0.8 V. So, for example, if you want a current limit of 180 mA, your R6 will be 0.8/0.180 = 3.3 Ω."
I wonder if by any chance there is a printing error and the value of 3.3ohm refers to R16 instead of R6 as it is written?
Sto ora per assemblare 4 PCB T-Reg per i primi due stadi di amplificazione del mio preamplificatore phono mm (che ha un totale di tre stadi di amplificazione, l'ultimo dei quali utilizza un giratore Ale Moglia). Per quanto riguarda il T-reg capisco che è bene mantenere la differenza tra tensione in ingresso e tensione in uscita entro 20V, mi chiedo se è possibile aumentare leggermente la differenza di tensione tra ingresso e uscita? (cioè rilasciare più tensione sul T-reg). Lo chiedo per sapere se ho un minimo di manovra per poter regolare la tensione in uscita dal t-reg mantenendo fissa una certa tensione in ingresso.
Good day Jan and all,
I have a practical question please.
I am developing an Push-pull class A amplifier. Required Uht=465V.
I calculated that before T-reg i need 535V (ripple only 4V because CRC filter). When mains voltage decrease -10%, before T-reg is 482V (4V ripple). So T-reg has enought voltage across for his work.
The opposite is the case when the mains voltage increase +10%. Before T-reg is 588V. This is still fine for a power transistor.
But what if there is a error in the amplifier and the amplifier stops drawing current (only 3mA drawing remains necessary for T-reg). Then the voltage before T-reg increases to 690V and this is too much for power transistor. I see it as a problem for a safe design. How do you see it?
PS: All this situations i simulate in PSUD2
I have a practical question please.
I am developing an Push-pull class A amplifier. Required Uht=465V.
I calculated that before T-reg i need 535V (ripple only 4V because CRC filter). When mains voltage decrease -10%, before T-reg is 482V (4V ripple). So T-reg has enought voltage across for his work.
The opposite is the case when the mains voltage increase +10%. Before T-reg is 588V. This is still fine for a power transistor.
But what if there is a error in the amplifier and the amplifier stops drawing current (only 3mA drawing remains necessary for T-reg). Then the voltage before T-reg increases to 690V and this is too much for power transistor. I see it as a problem for a safe design. How do you see it?
PS: All this situations i simulate in PSUD2