±15 is a generic term that refers to the regulated voltage for the op-amps. I can't believe I had to explain that. The 393 isn't an op-amp, it's a comparator and likely part of the protection circuit.
10uS (not 10mS) and 5v/div is a good starting point. Set the scope to AC coupling. If you don't see a square wave, measure the DC voltage on each of the outputs (black probe on leg 3 and red probe on leg 1)
If the drive signal is good and the outputs are good, I'd suspect something in the output filter. Reinstall the outputs, clamp them and power it up through a current limiter and twist the inductor. Does the current draw change?