By my calculations you would have about a 6.27 AWG wire if these strands of 8,12, and 18 were parallel (25.05943738 mm2 wire area). But if they were just serial, or one attached to the end of another then the smallest diameter wire (18) is the bottleneck and therefore your total “size” is 18awg.
The distance and resistance also comes into play.
use a calculator like this to work that out.
http://www.electrician.com/vd_calculator.html
Since internal wire is generally short it can also be thinner, Speaker wire generally needs to be a thicker since it runs many many times the distance of the internal wire.
use a calculator like this to work that out.
http://www.electrician.com/vd_calculator.html
Since internal wire is generally short it can also be thinner, Speaker wire generally needs to be a thicker since it runs many many times the distance of the internal wire.
gotcha, thanks for the answer.officeboy said:The distance and resistance also comes into play.
use a calculator like this to work that out.
http://www.electrician.com/vd_calculator.html
Since internal wire is generally short it can also be thinner, Speaker wire generally needs to be a thicker since it runs many many times the distance of the internal wire.
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