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    Building, troubleshooting and testing of these amplifiers should only be
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    the safety precautions around high voltages.

cascode vs asymmetrical cathode coupled

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#40

tubetvr said:
... However if you use the same formula for a low µ power triode as a 6C33C the result is very inaccurate. A 6C33C has a µ of typically 2.7 and a Rp of 80 ohm which gives a gm of 33.75mA/V, with the faulty formula this would give an output impedance of 1/gm which in this case is 29.6 ©. If we instead use the correct formula Zo = 1/[(1/Rp)+gm] we get 21.6 © a 37% difference which can't be seen as insignificant. ... Regards Hans

gm = Rp / (µ+1) = 80Ω / (2,7+1) = 21,6Ω
There is 0% difference. :yes:

I got gm from the data book. :confused:
What do you want to suggest here? :mad:

No comments to the other text, this is a moderators job.

D.
 
Re: Re: #40

oldeurope said:




1/gm = Rp / (µ+1) = 80Ω / (2,7+1) = 21,6Ω
There is 0% difference. :yes:

Darius

I think you missed the point. The problem is that 1/gm is NOT the correct formula for output impedance, it is only an approximation in the limit of mu>>1. If you look at the output impedance, this formula gives a 30% error for Hans's example.

And, once again, by definition, gm = mu/rp, NOT (mu + 1)/rp.
 
no problem ...

Originally #46 posted by SY


I think you missed the point. ... If you look at the output impedance, this formula gives a 30% error for Hans's example.

And, once again, by definition, gm = mu/rp, NOT (mu + 1)/rp.

Hi SY,
now I am totally confused.:confused: I'll think about it.

Most important is this :
Originally #46 posted by SY


... The problem is that 1/gm is NOT the correct formula for output impedance, it is only an approximation in the limit of mu>>1. ...
The ECC83 12AX7 has definitely µ>>1. Thus my calculation is correct. ;)

Back to topic please, thanks!

Kind regards,
Darius :)
 
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