Dear All:
I am using a cmoy design amplifier using a voltage divider to create a "virtual ground" (8v/2) = 4v.
Is there a problem if i connect the virtual ground (4v) of the amplifier to a real ground in the analog source?
For example if I connect a jack to my computer headphone output there will be a difference of 4v between the "virtual ground 4v" vs the real ground of my computer jack connector.
I'm confused.
Regard.
Alfredo Mendiola Loyola
Lima, Peru
I am using a cmoy design amplifier using a voltage divider to create a "virtual ground" (8v/2) = 4v.
Is there a problem if i connect the virtual ground (4v) of the amplifier to a real ground in the analog source?
For example if I connect a jack to my computer headphone output there will be a difference of 4v between the "virtual ground 4v" vs the real ground of my computer jack connector.
I'm confused.
Regard.
Alfredo Mendiola Loyola
Lima, Peru
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Every voltage is the difference in potential between two places. No one place has a voltage. So you need to ask yourself: with respect to what is the virtual ground at 4V? Another question is: what is the voltage at one terminal of a battery?
I'm using a 8 volts power supply, but I can replace that power supply by an 8v battery.
+4v (8v with respect to 4v)
-4v (0v with respect to 4v)
Regards.
Alfredo
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