This will be the speakers, a so far non commercial experiment by Andres.
The driver is a Visaton B200. I am currently working on a wideband driver that shall compete with the Visaton.
I remember those, smoking (and then we all payed).
Although I am sure this has been asked and answered several times before - have mercy, I don't wanna skim the whole thread:
How much current will one channel of Paradise R3 draw (per rail)?
According to my notes it is about 80mA (the CCS is set to 110mA).
Andres will bring an unusual cartridge. It has only 0.25mV output and 65 Ohm. That is because the windings of the coils are not on magnetic material and the magnet is far from the coils. A tough combination. I hope it works with the Paradise.
One advantage of that cartridge is very high channel separation to high frequencies, at least that was told to me.
One advantage of that cartridge is very high channel separation to high frequencies, at least that was told to me.
No. 110 mA. The 50 mA "overshoot" will be burnt by the shunt reg.So total current consumption will be 160mA right ?
No. 110 mA. The 50 mA "overshoot" will be burnt by the shunt reg.
???
80mA per side(+-)... each channel has two shunts running at 110mA
I believe total shunt consumption will be 220mA per channel but each channel amp needs 2 x 80mA to operate right ?
In each side(+-) the shunts will dissipate 30mA more than the 80mA needed right ?
Andres will bring an unusual cartridge. It has only 0.25mV output and 65 Ohm. That is because the windings of the coils are not on magnetic material and the magnet is far from the coils. A tough combination. I hope it works with the Paradise.
One advantage of that cartridge is very high channel separation to high frequencies, at least that was told to me.
It works wondefully with a DL160 (140ohms)
???
80mA per side(+-)... each channel has two shunts running at 110mA
I believe total shunt consumption will be 220mA per channel but each channel amp needs 2 x 80mA to operate right ?
In each side(+-) the shunts will dissipate 30mA more than the 80mA needed right ?
You win the grand price 2x 110mA burning 2x 30mA delivering 2x 80mA.
No. 110 mA. The 50 mA "overshoot" will be burnt by the shunt reg.
See http://www.diyaudio.com/forums/analogue-source/154210-mpp-716.html#post3149555
Of course. 110 mA CCS setting minus 80 mA real deal makes 30 mA difference to be absorbed by the shunt, not 50. Sry for the bad math.
As I am going to use a 2x40V O-core transformer per channel, I will have to get rid of about 3,3 VA or 30 Volts at 110 mA with an passive LCLCLC thing (or so). Should be possible.
As I am going to use a 2x40V O-core transformer per channel, I will have to get rid of about 3,3 VA or 30 Volts at 110 mA with an passive LCLCLC thing (or so). Should be possible.