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How to calculate source impedance for audio transformer?

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Hi dear guys,

Sorry to ask a question again at the same day...:eek:

I would like to use different audio transformers as a symetrical line driver with a Zout of 600Ohm. I have two transformers with 2:1 ( Lundahl LL5402 and A262-A2E ) and one 5:1 ( Sowter 9041 ).
The question is how to identify the best source impedance of the driver stage to drive the transformers in the best mode?

Example:
A LL5402 has an primary impedance of 2K4 at a load of 600Ohm. For best power adjustment the source and load impedance should be the same. But for audio signals a voltage adjustment should be the target. So the source impedance should be low as possible.

Do you have any examples or hints how to calculate it??

Thanks a lot!
Karsten
 
Impedance ratio = square of turns/voltage ratio.

So if the turns or voltage ratio of a transformer is 2:1, then the impedance ratio is 2^2:1, or 4:1. Your 5:1 transformer by that logic as a 25:1 impedance ratio.

If the secondary impedance is 600R, then the 2:1 (turns/voltage) will reflect a 2k4 primary impedance, and the 5:1 (turns/voltage) will look like a 15k load on the primary side.
 
Impedance ratio = square of turns/voltage ratio.

So if the turns or voltage ratio of a transformer is 2:1, then the impedance ratio is 2^2:1, or 4:1. Your 5:1 transformer by that logic as a 25:1 impedance ratio.

If the secondary impedance is 600R, then the 2:1 (turns/voltage) will reflect a 2k4 primary impedance, and the 5:1 (turns/voltage) will look like a 15k load on the primary side.


Then there are a couple of wrinkles.

First, the low frequency response is determined by the transformer primary inductance and the impedance of the source driving it. Higher primary inductance and lower source resistance give better LF response.

HF response is determined by winding capacitance and leakage inductance. Both tend to increase with inductance so improving the LF response can be at the detriment of HF response.

Cheers

Ian
 
Hello,
Thanks a lot four your help!

Well, I think I formulate my question to inaccurate; sorry.
The question is not how to calculate the primary impedance using the coupling ratio. That´s so far easy if we assume an ideal transformer.

Assuming I would like to drive the output transformer using a CF stage and the transformer has an 5:1 coupling. In this case the primary impedace will be 15K while the secondary is 600Ohm.
Which output impedance should I calculate in best case for the CF driver?

Thanks and sorry for my bad english...

Karsten
 
Assuming I would like to drive the output transformer using a CF stage and the transformer has an 5:1 coupling. In this case the primary impedace will be 15K while the secondary is 600Ohm.
Which output impedance should I calculate in best case for the CF driver?

A lot depends on how much power you want to deliver to the load. The output impedance of the CF will be a few hundred ohms or less but that is not the important factor. What is important is how much idle current the CF stage has because that determines how much power it can deliver.

The other factor is voltage swing. If you want to deliver up to 10V rms into the load and you have a 5:1 transformer then the primary signal will need to be able to swing 50V rms or 141 volts peak to peak which is asking a lot of a CF.

If you can tell is exactly what maximum voltage into what load you need then we can help you better.

Cheers

Ian
 
Hey,

So sorry to be to imprecice. I would not write looong mails...

I want to drive an output transformer to get a symetrical signal with 600Ohms output impedance to connect XLR connectors. Typical usage is as an example a DI-Box.
There are some schematrics in the net which I can use but I want to understand how to drive a transformer by an Tube in such a case. The idea is to play with different transformers and driverstages like CF, SRPP and Cascode. To do that I need to understand how to match the output impedance of the driver stage to the transformed input impedance of the transformer and which effect this will have.
The power which I have to transfer is minimal, also the voltage is mostly a so called "microfon Level" wich is nomial -20dBu.
My understanding is, that I do not need a Power-matched alignment between the driver stage output impedance and the transformers primary input impedace ( on 600 Ohms load secondary ). All what I need is a quite low output impedance of the driver stage ( less as possible ) and a matching signal swing to the coupling factor of the transformer to reach the necessary output voltage I think.
But I don´t really know if this assumption is right or if there is someting important other things to be taken in account.

Thanks a lot for your patience with my bad english and my smattering knowledge how to drive a transfomer...

Best regards
Karsten
 
Karsten,

Transformers are not "driven" as such, but you drive the next stage "through" the transformer.
There is much info available of how transformers work; what they do and what they don't do.
Don't you think it makes more sense to do some investigation yourself?
This is not meant in a negative way, but just for your own understanding, and what would the requirements be for driver stages and "driven" stages.
One thing for sure: cascodes and transformers are a no-go territory because of the generally very high output impedances of cascodes (comparible with pentodes in this respect as far as driver stages are concerned).
 
Peter,
O.K. You might be right. It´s one way of success to work fully in theoretical level and than try to be go physical.
I take up your advice first to go deeper in the theory of transformers and tube driver stages.

So thanks a lot dear wise guys! I go back now, switch the soldering iron off and open some books...

Have a nice weekend!

Karsten
 
The power which I have to transfer is minimal, also the voltage is mostly a so called "microfon Level" wich is nomial -20dBu.
My understanding is, that I do not need a Power-matched alignment between the driver stage output impedance and the transformers primary input impedace ( on 600 Ohms load secondary ). All what I need is a quite low output impedance of the driver stage ( less as possible ) and a matching signal swing to the coupling factor of the transformer to reach the necessary output voltage I think.n

Hi Kartsten,

That is good information. You only need to 'power match' if you want to transfer significant power. You only need to transfer -20dBu into 600 ohms which is NOT significant power so you are correct in your assumption that you should aim for as low an output impedance as possible.

Cheers

Ian
 
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