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Tapped capacitor impedance matching along with power conservation..?
Tapped capacitor impedance matching along with power conservation..?
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Old 8th November 2019, 02:46 PM   #11
brainbaby is offline brainbaby
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Quote:
Originally Posted by Mark Tillotson View Post
in (b) the tap between L and C prevents this cancelation, its takes a bit of algebra to figure out the formula.
Could you please elaborate your point.."tap prevents cancellation..."

I am thinking this way....the parallel RC combination is transformed into series equivalent with a new value of Rs and new value of capacitance (C1//C2)...let say Ceq..which is in series with Ls due to parallel to series conversion..
Now as per your statement the tap prevent the cancellation of impedance of reactive components at resonance...so it implies that Ceq and Ls will have some impedance (which won't cancel)and will contribute to some power dissipation in the circuit along with Rs.

So mathematically Power = VI and in case b) Vo*Io = individual power dissipation along Ls,Ceq and Req..(as with the absence of the tap, Power dissipation of circuit (Vo*Io) will be equal to power dissipation among Rs only............your comments...
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Old 8th November 2019, 02:57 PM   #12
brainbaby is offline brainbaby
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Originally Posted by DF96 View Post
It is a compensatory change in order to preserve the same power in the circuit.
Yes it feels better to me hearing what I expected...but the problem is its an assumption ....not proved yet..
I am still not sure whats that compensatory change is...may be its the increase in the output voltage...If the output voltage is increase then there might be something in Ls Ceq or Req.. that might have changed.....and in order to balance it Vo has increased
but first lets see what Mark has to comment...then see where the discussion goes..
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Old 9th November 2019, 11:48 AM   #13
DF96 is offline DF96  England
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C and L do not dissipate power, they merely store it for a while. Only R can dissipate power.

Adding the extra capacitor between the tuned circuit and the outside world can be considered to reduce the coupling between them. It increases the external voltage needed to get a particular internal current going.

From this distance it is difficult to peer inside your head and see exactly what it is that puzzles you. We don't know what assumptions you are making, so we cannot know which of them are right and which are wrong. We don't know at what level you are thinking about electronics: absolute beginner who is struggling to understand any circuit and so is trying to run before he can walk, experienced amateur who has just encountered energy conservation as a circuit analysis technique for the first time etc.
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Old 10th November 2019, 12:11 PM   #14
brainbaby is offline brainbaby
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Quote:
Originally Posted by DF96 View Post
C and L do not dissipate power, they merely store it for a while. Only R can dissipate power.

Adding the extra capacitor between the tuned circuit and the outside world can be considered to reduce the coupling between them. It increases the external voltage needed to get a particular internal current going
.
I got your point...Actually due to the presence of capacitive network current divides and reduces in the output branch. Power equals VI, hence I changed here and to maintain a constant power V changed to the same amount, this amount depends upon the ratio of capacitances (which varies the current in the circuit).
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