calculation of resistor value in CR circuit of B+

[classicyip]

hey folks, I wanna ask for advice.
Let say if I am making a SET of 2A3 driven by 6SH7,
and I wanna make a power supply for both 320V and 180V, using capacitor and resistor circuit to "drop" the 320V to 180V?
how can I accurately calculate the resistor value for it ?

thanks

 

[pinholer]

Assuming that the 6SH7 is operating in triode mode and the plate current is 10 mA, then using Ohm's Law (R = V / I):

R = (320 - 180) / 0.01= 14 000 or 14k ohms

The operating point of the 6SH7 in your circuit may be different, so you may have to recalculate using your actual operating current.

 

[classicyip]

thx pinholer, but let say the circuit shown below , the math doesnt work ;
the voltage drop at 6SL7 end is too small if use of the presumed current draw by 6SL7 x tWO 2k2 resistor ........

 

[Salas]

It does not show up. Better not

 

[classicyip]

thank you, here is the schematic

 

[JMFahey]

thx pinholer, but let say the circuit shown below , the math doesnt work ;
the voltage drop at 6SL7 end is too small if use of the presumed current draw by 6SL7 x tWO 2k2 resistor ........

Why would it?
You ask about:

320V and 180V .... 6SH7 ....

While your schematic shows:
* NO 6SH7
* NO 320V
* NO 180V
anywhere.

 

[DF96]

the voltage drop at 6SL7 end is too small if use of the presumed current draw by 6SL7 x tWO 2k2 resistor ........

What current draw do you presume for a 6SL7? What has that got to do with your circuit?