Selenium rectifiers have a voltage drop of about 1V per plate. A 400V rectifier would have about 16 plates. Even at 100mA you'd lose more in the rectifier than the load.
They smell bad too
More: the AEG that I have 21.4V.
Could you explain why not in a more elaborate way to understand better your answer please?
The 100mA is a limit for current and is allowed in the conducting state.
In that condition there is not the 400V across it, only the forward drop (16 or 21V).
The 400V is a limit in the reverse direction, what it can withstand without breaking over. In that condition, the current through the diode is essentially zero (save some leakage).
So the two limits are for two separate conditions, they have no relation with each other.
In that condition there is not the 400V across it, only the forward drop (16 or 21V).
The 400V is a limit in the reverse direction, what it can withstand without breaking over. In that condition, the current through the diode is essentially zero (save some leakage).
So the two limits are for two separate conditions, they have no relation with each other.
Selenium rectifier? Are you restoring antiques or so? Given the voltages that is not likely. Selenium is unsuitable applications at any voltage.
Any silicon diode will do better, 1N4001, 1N5408.
If you need a low voltage drop, find some diodes in an old PC PSU. The diodes often are Schottky with a forward voltage drop of 0.2V
You calculation is incorrect. Diode dissipation is
.
For silicon use 1V forward drop.
Any silicon diode will do better, 1N4001, 1N5408.
If you need a low voltage drop, find some diodes in an old PC PSU. The diodes often are Schottky with a forward voltage drop of 0.2V
You calculation is incorrect. Diode dissipation is
Code:
voltage drop x currentFor silicon use 1V forward drop.
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