Zener+Voltage follower

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When I looked at the data sheet on the BF862 at least to me it looks like it would
be a poor choice for a ccs. Especially like you will be using it in your circuit where you will have less than 3v VDS. I would think a simple resistor would work better here than that device. I think you may want to look at figure 8.file:///C:/Users/Woody/Downloads/datasheet.pdf
 
Ketje,Thx!
Just curious how did you make changes to the schematic so fast? Or is it something you already made and using?
Simply Paint :)
I was not sure if I was connecting the pins of JFEt right to use as current source.Please check for me.
That's ok, chose for Idss= 5...10mA and a knee voltage not to high. Little mod on the output gives 0.6V more room for the fet.
Mona
 
Thanks Mona. I also noticed you changed the 1N4148 with an LED. What is the reasoning behind it?
What are the specs of LED or is it not relevant?
You need a reference voltage of 6 volts + Vbe.With a diode + zener the zener has to be 6volt.But 6volt zener isn't easy to find.A 5.1volts is , + 1.5 from a LED =6.6V. As long as the total LED (or an other voltage dropper) + zener = 6.6 volts you get 6 volts out.
Mona
 
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Attached below are the IDSS curves of eight JFETs that happened to be rattling about in my parts box. There are within spec but a little on the high side; somebody else must have gotten the shipment of low-IDSS parts I suppose. Feel free to eyeball-extract the incremental resistance at VDS=2.4 volts if you wish; take the slope of the tangent line and recall that r = deltaV/deltaI. I get 1.6Kohms but might be mistaken.

Line Regulation (= deltaVout / deltaVin) at DC is set by a simple voltage divider, whose pullup is the JFET incremental resistance, and whose pulldown is (Zener incremental resistance + 1N4148 incremental resistance). Vishay's datasheet suggests that the zener is 20-30 ohms, and LTSPICE suggests that the 1N4148 is 2.6 ohms.

So if Rpullup=1600 and Rpulldown=27.6 then Line Regulation is -35 dB. Or thereabouts.

_
 

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Set Vin = 9.0 volts. Measure Vout.

Set Vin = 9.1 volts. Measure Vout again.

Then "Line Regulation" = (Vout2 - Vout1) / (9.1 - 9.0).

I estimate that with a 2N5459, 1N4148, and BZV85-C5V1 as shown in post #1, your circuit's Line Regulation will be no better than (27.6 / 1627.6) = 1.70% = -35 dB. Replacing the 1N4148 with an LED will make Line Regulation slightly worse because the incremental resistance of an LED is higher than the incremental resistance of a 1N4148.

For every volt of change on Vin, your Vout will change approx. (1.70% of 1V) = 0.017 volts.

To put that in perspective, the Fairchild uA723 integrated circuit voltage regulator came out in 1972; its Line Regulation was 0.1%. More modern voltage regulator ICs have Line Regulation specs that are 100 times lower.

But you might be perfectly happy with what you've got here. It's your decision, nobody else's.
 
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