Impedence question
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 Multi-Way Conventional loudspeakers with crossovers

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 9th January 2004, 01:31 PM #1 squidbait   diyAudio Member   Join Date: Dec 2003 Location: Detroit Area Impedence question How are most loudspeakers wired? I believe two 8 ohm speakers wired in parallel equals 4 ohms, and two 8 ohm speakers wired in series equals 16 ohms. Where I get confused is, what happens when you start wiring 3 or 4 speakers together. How do you keep the impedence in check. I have a Denon 3802 (I think) and don't know what it's rated for.
roddyama
diyAudio Moderator Emeritus

Join Date: Jan 2002
Location: Michigan
The total resistance of any number of series resistances are just the sum of individual resistances.
The total resistance of equal valued resistances is the resistance value divided by the number of parallel resistances (ie. 4 - 8ohm resistors in parallel = 8/2 = 2ohm)
the total resistance of a number of non-equal resistances in parallel can be calculated using the equation below.
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Rodd Yamashita

 9th January 2004, 03:05 PM #3 squidbait   diyAudio Member   Join Date: Dec 2003 Location: Detroit Area Can most amplifiers handle raitings down to 2 ohms? Why would you ever wire them in series?
 9th January 2004, 03:08 PM #4 ProsonOnkyo   diyAudio Member   Join Date: Jan 2004 Location: Inside a subwoofer somewhere in norway... I have a Onkyo TX-SR600E 6.1 amplifier, but i want two speakers in the rear channel. the speakers i want on the rear channel is 6 ohm, and the resistanse should be between 4-16 ohm... Is it possible to do this?
 9th January 2004, 03:32 PM #5 rabbitz   diyAudio Member     Join Date: Jul 2003 Location: Newcastle, Australia 2 ohm for an amp is not a good idea and will probably end up with heaps of smoke. If you want 4 drivers, wire them in series/parallel which gives you the impedance of the single driver. Have a look at this primer for details. http://www1.jaycar.com.au/images_uploaded/crossovr.pdf

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