|
Home | Forums | Rules | Articles | diyAudio Store | Blogs | Gallery | Wiki | Register | Donations | FAQ | Calendar | Mark Forums Read |
Multi-Way Conventional loudspeakers with crossovers |
|
Please consider donating to help us continue to serve you.
Ads on/off / Custom Title / More PMs / More album space / Advanced printing & mass image saving |
![]() |
|
Thread Tools |
![]() |
#1 |
diyAudio Member
Join Date: Aug 2001
Location: South East, UK
|
![]()
Blimey im asking a bit today
![]() So its pretty late and i might not be thinking too straight but here we go... I've decided it is now time to time align, or at least get the measurements for time aligning my Mid/bass and tweeters, im doing this by whacking both of them in their box, back panel taken off, and the tweeter wired into the left channel of an amp and the mid/bass wired into the right side of an amp pointing my measurement mic somewhere in the middle of the drivers about 0.5 m back. I then run 2 phase shifting sine waves (3.5k (cross over frq) )one for each channel and freeze the playback of the waves when measurement mic - coupled to PC oscilliscope - tells me output is highest, and then i measure the pahse difference and work out how much i need to offset the drivers. As far as i can tell this part of my method isnt flawed however... When i whack the back on the box, add a little stuffing ![]() Thanks, Beggar |
![]() |
![]() |
#2 |
diyAudio Moderator Emeritus
Join Date: Oct 2002
Location: Chicagoland
|
Well, "phase" encompasses a lot, including shifts from driver rolloffs. What you really want to measure to determine driver offsets is the offset in the acoustic center. The best way to do this is to take individual impulse responses from the drivers at a fixed mike position, unwrap the phase curves to get to a minimum phase condition and note time-of-flights, then subtract time-of-flights and multiply that delta-time by speed of sound to get the offset.
This is covered in exquisite detail in d'Appolito's book on loudspeaker measurement.
__________________
"You tell me whar a man gits his corn pone, en I'll tell you what his 'pinions is." |
![]() |
![]() |
#3 |
diyAudio Moderator Emeritus
Join Date: Apr 2002
Location: Rotherham, England
|
Or a "seat of the pants" method is to feed a sinewave in at crossover frequency, measure with a mic and a 'scope, and adjust 'till you get a nice wave.
![]()
__________________
“One of the poets, whose name I cannot recall, has a passage, which I am unable at the moment to remember, in one of his works, which for the time being has slipped my mind, which hits off admirably this age-old situation.” ― PG Wodehouse |
![]() |
![]() |
#4 |
diyAudio Moderator Emeritus
Join Date: Oct 2002
Location: Chicagoland
|
The problem with that is that it conflates phase difference from delay with phase difference from rolloffs. Because one is minimum phase and the other isn't, optimizing at one frequency will not guarantee optimization at others.
It's such an easy measurement to do that there's no need to use shortcuts.
__________________
"You tell me whar a man gits his corn pone, en I'll tell you what his 'pinions is." |
![]() |
![]() |
#5 |
diyAudio Member
Join Date: Aug 2001
Location: South East, UK
|
So what your saying is that changing the enclosure size (plonking the back on, and sealing the tweeter off) after time alignment measuring wont affect the time alignment measurements....
I think/ I hope.... Thanks for responses! Beggar ![]() |
![]() |
![]() |
#6 |
diyAudio Member
Join Date: Aug 2001
Location: South East, UK
|
hey, cool done my measurements
![]() Well i tried to do all 3 methods and failed on one count as i dont actually know how to find the phase response of a cone, i guess i could have written a program to do it, but there's probably already one around somewhere, ah well. Well my method yeilded a result that at 3500hz the cones were approx 212 degrees out of phase, and the move it fwd and back method (trusting my ear!) hinted at the same thing, so i fliped the tweeter 180 out of phase and hey presto this verified 32 degrees out of phase, means i recess the mid/bass about 8.5 mm into the baffle with a phase reversed tweeter, yey ![]() ![]() As always thanks very much for everyone's help, Beggar ![]() |
![]() |
![]() |
#7 | |
diyAudio Moderator Emeritus
Join Date: Oct 2002
Location: Chicagoland
|
Quote:
__________________
"You tell me whar a man gits his corn pone, en I'll tell you what his 'pinions is." |
|
![]() |
![]() |
#8 |
diyAudio Member
Join Date: Jan 2003
Location: Zurich
|
One of the most misunderstood concepts in speaker design is "time alignment." Time alignment doesn't actually involve time aligning the drivers, it involves intentionally misaligning the drivers to offset delay in the crossover. A couple of points are worth clarifying here:
1) most standard (symmetric) filters are designed to sum flat electrically. To get these crossovers to sum flat acoustically, the acoustical centers of the drivers have to be aligned in the crossover region. However, the crossover introduces a delay on the woofer, andso a system (drivers plus crossover) will not be time aligned if the drivers are time aligned (unless you areusing a firstorder crossover). 2) the idea of time alignment (as introduced by Ed Long) is to deliberately move the woofer forward of the tweeter so that the system is time aligned. However, if you do this with a crossover that sums flat electrically, then the system won't sum flat acoustically. 3) in order to get time alignment and a flat summed magnitude response, you have to use an asymmetric filter--higher slope on the woofer than on the tweeter and this crossover will not sum flat electrically. You can look at the following papers in the AES Loudspeaker Anthology for an idea how to do this: "Loudspeaker Driver Phase Response: The Neglected Factor in Crossover Design" by Marshall Leach Jr. "Acoustic Alignment of Loudspeaker Drivers by Nonsymmetric Crossovers of Different Orders" by B. Hillerich "Time Offset and Crossover Design" by Dennis Fink If you want a truly time aligned system, then you'll have to design a crossover meant for the purpose. If, on the other hand, you're just trying to optimize the setup of your current crossover/driver combination, I wouldn't worry about time alignment because you're not going to get it anyway. It is better to play around moving the relative positions of the drivers back and forth until you get the flatest frequency response possible. I hope that helps, John |
![]() |
![]() |
#9 |
diyAudio Member
Join Date: Aug 2001
Location: South East, UK
|
hey john thanks for the advice
![]() Thing is im building up a set of speakers (2 way satellittes and 1 sub) from scratch, which only use the 4th order Linkwitz-Riley Xovers and identical midrange and high amplification lines, so no relative phase difference will be introduced at any point apart from the speakers. For these im after a smooth phase transition at the crossover point (3.5khz) so i dont loose intelligibility (think thats the right spelling/word) you caught me just as i was about to cut some 4cm baffle raising things to mount my midrange cones on. At this moment in time the biggest thing on my mind is baffle diffraction (a slight insight into my somewhat uncomplicated life ![]() edit: oh yeah forgot to mention last night i realised how dumb i'd been, i though (for some reason) that flipping the tweeters polarity would equate to a 180 degree phase shift, wrong! Thanks Beggar |
![]() |
![]() |
#10 | |
diyAudio Member
Join Date: Dec 2002
Location: Planet Earth
|
Quote:
|
|
![]() |
![]() |
Thread Tools | |
|
|
![]() |
||||
Thread | Thread Starter | Forum | Replies | Last Post |
DIY Time Alignment. | clipto333 | Car Audio | 32 | 4th January 2011 05:48 AM |
Don´t waste time with changing op-amps | John007 | Digital Source | 81 | 12th August 2008 06:24 AM |
You may laugh..but don't waste your time trying to dissuade me. 300B preamp. | Bas Horneman | Tubes / Valves | 56 | 21st July 2005 02:00 PM |
New To Site? | Need Help? |