this is my first thread
and i dont know how to attach the image here
MYDOUBT : Diode Voltage Clipper
( IMAGE IS IN THE LINK )
the clipper circuits clips the input signal (voltage signal) which depends on the circuit .
in the above mentioned circuit which is in the link the positive peak is clipped above the reference voltage
but there is resistor at the input side . if there is a resistor then the voltage should be dropped to some value
but if we observe in the figure there isnt any voltage drop
see the negative peak the amplitudes for the - ve peak at output is same as input
why there isnt any voltage drop even if we place a resistor at the input side ???
thanks for answering
srikarsana
and i dont know how to attach the image here
MYDOUBT : Diode Voltage Clipper
( IMAGE IS IN THE LINK )
the clipper circuits clips the input signal (voltage signal) which depends on the circuit .
in the above mentioned circuit which is in the link the positive peak is clipped above the reference voltage
but there is resistor at the input side . if there is a resistor then the voltage should be dropped to some value
but if we observe in the figure there isnt any voltage drop
see the negative peak the amplitudes for the - ve peak at output is same as input
why there isnt any voltage drop even if we place a resistor at the input side ???
thanks for answering
srikarsana
Last edited:
Please, can you explain better? Which is the question? Circuit?
This way we can help better.
It seems that source (Vin) is assumed to be ideal, meaning that it can supply an infinite amount of current. If you add a source resistance like the resistor shown, it is implied that all the current that is flowing through the resistor can flow to ground through the diode (when it conducts), resulting in the hard clipping waveform that is shown. Another way to think about it, is that the diode and resistor form a voltage divider but the resistance of the ideal diode is zero when it is conducting.
Without the resistor, although an infinite amount of current would flow through the idea diode, there is still infinitely more current left to flow forward and the voltage would appear the same. Funny thing, this infinity!
If you add another resistor to the leg leading to the diode, when the diode conducts you will get a voltage divider by the ratio of the resistances and the clipping will be "softer".
To answer your other question, the output is an open circuit, e.g. infinite resistance. When the diode is not conducting there is essentially zero current flowing out of the source so there will be no voltage drop across the resistor.
Without the resistor, although an infinite amount of current would flow through the idea diode, there is still infinitely more current left to flow forward and the voltage would appear the same. Funny thing, this infinity!
If you add another resistor to the leg leading to the diode, when the diode conducts you will get a voltage divider by the ratio of the resistances and the clipping will be "softer".
To answer your other question, the output is an open circuit, e.g. infinite resistance. When the diode is not conducting there is essentially zero current flowing out of the source so there will be no voltage drop across the resistor.
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