formula for Q of Helmholtz resonator

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what I'm thinking is that different port length/cross section combinations (for the same freq & box size) will give different Qs, thus having different effects on the bandwidth & level of bass freqs, yet changing the ratios of port length/cross section while keeping everything else constant in box sim programs doesn't have any effect on the freq response shown, what am I missing?
 
Hi,

The Q of a port treated as a hemholtz resonator has very
little to do with the Q of a vented boxes bass alignment,
as its a coupled resonating system, not one system.

Basically the port "q" simply should be high enough not
to matter much. The main damping in the system comes
from the driver. Damped ports (e.g. drinking straws)
are hard to model AFAIK, best done empirically.

rgds, sreten.
 
Re:'The Q of a port treated as a hemholtz resonator has very
little to do with the Q of a vented boxes bass alignment" - so i guess I'm trying to quantify that 'very little'

re:' the port "q" simply should be high enough' - don't you mean low enough? (I guess that could be a preference thing though, this is part of what I'm trying to explore), and again, it would be good to quantify 'enough'.

(Just to make it clear, I'm not talking about the Q of a port as a resonating pipe, but the Q of the whole box/port combo)
Perhaps I need to wade though those Thele/Small papers again, wish my maths was up to it...
 
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let me put up a hypothesis to be shot down (Subjective language warning): Ignoring the effects of port turbulence & reflections coming through the port, a short port giving a lower helmholtz resonance Q will sound more natural than a long port that results in a higher Q ...???
 
Hi,

Again your equation only relates to a port connected to a closed box
with no driver in it and has nothing to do with the Q of a vented boxes
bass alignment. I haven't looked at it in detail as it does not matter.

For a box port to work well its Q has to be high enough so it doesn't
matter much, most of the damping and losses come from the driver.

If you reduce the port Q, by adding port damping of some form most
box sims simply can't handle it, and you'll get a response somewhere
between sealed and "normal" vented. Aperoidic damping is a special
case most sims can't handle either, where no phase inversion takes
place in the port and it can reduce the Q of a sealed alignment,
(by leaking out of phase bass that cancels with driver output).

As you have noted, in Sims changing the port size keeping the same
frequency has no effect on the small signal response / bass alignment.

That is because the Sims assume the port is an undamped resonator,
i.e. infinite Q, in practice port Q just needs to be high enough for the
Sims to be accurate enough for the bass modelling they present.

Port sizes are chosen based on the smallest total volume that
works well with the large signal parameters of the driver, often
port blocking is arranged to coincide with the driver reaching
its excursion limits, compensating for increasing driver Q.

rgds, sreten.
 
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