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Do this R-2R ladder works?
Do this R-2R ladder works?
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Old 14th July 2019, 01:52 PM   #1
bluealbin is offline bluealbin
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Join Date: May 2017
Default Do this R-2R ladder works?

Do this R-2R ladder works? it requires less resistors and less tolerance, just 8bit +8bit equals to 16bit.

I know it need a complex logic to control such ladder, but i am not capable to figure it out yet.

Will it work? sound ok? I happen to get the word "R-2R" from google, and have no knowledge about electronics.
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Old 14th July 2019, 02:55 PM   #2
MarcelvdG is offline MarcelvdG  Netherlands
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Basically you designed a circuit that multiplies two unsigned 8 bit words while converting the product to analogue. For audio you would need to make it signed somehow, but on top of that, you can't convert any prime numbers greater than 256, nor composite numbers having a prime factor greater than 255 - or at least not accurately, you would have to round them to a near composite number with all prime factors smaller than 255.
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Old 18th July 2019, 06:15 PM   #3
Mark Tillotson is offline Mark Tillotson
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Location: Cambridge UK
16 bit dynamic range, but only 8 bit accuracy, and crazy loads of missing codes with
much patterning/structure. Good way to create odd effects in a synth perhaps?
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Old 23rd July 2019, 03:55 AM   #4
Monte McGuire is offline Monte McGuire
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Do this R-2R ladder works?
I don't see this as using fewer resistors than a standard R-2R ladder, and if you want no missing codes, as Mark said you have to use tight tolerance resistors - basically all have to be good to one part in 2^17 or 10ppm. No free lunch here.
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Old 23rd July 2019, 04:23 AM   #5
MarcelvdG is offline MarcelvdG  Netherlands
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Monte McGuire, please read post #2. It doesn't even work properly with zero tolerance resistors.
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