Hi guys, I'm writing you cause I have one doubt about the driver stage supplying of this Cxd400 module. On Connex website I found:
"For increased efficiency the driver stage can be supplied separately with an regulated or unregulated voltage in range of 15-25V DC at 60mA max. An isolalted supply voltage is required because the – is connected on board to -Vcc."
Ok. Then I look at the amp board and I find a 2 pins connector, one marked " Vd", the other marked "-Vcc". Does it need a dual DC power supply? How can I realize such a PS? Starting from an AC - 0 - AC transformer followed by a double rectifier stage? And if yes, and therefore the output of this supply will be like V+ GND V-, what how should I manage the GND? I hope I'm explining well enough and I'm sorry if questions may seem stupid, but I'm trying to learn.
Thanks in advance,
Gaetano
"For increased efficiency the driver stage can be supplied separately with an regulated or unregulated voltage in range of 15-25V DC at 60mA max. An isolalted supply voltage is required because the – is connected on board to -Vcc."
Ok. Then I look at the amp board and I find a 2 pins connector, one marked " Vd", the other marked "-Vcc". Does it need a dual DC power supply? How can I realize such a PS? Starting from an AC - 0 - AC transformer followed by a double rectifier stage? And if yes, and therefore the output of this supply will be like V+ GND V-, what how should I manage the GND? I hope I'm explining well enough and I'm sorry if questions may seem stupid, but I'm trying to learn.
Thanks in advance,
Gaetano
Yes, it needs a "dual DC" power supply, ie. a +/- [a few tens] V DC. That can be achieved with a center-tapped secondary on a transformer, indeed, but one bridge rectifier is enough.
Additionally though, it will also require a third voltage, that "anything between 15 and 25V DC", which is (and here's the key part) referenced to the -VCC rail.
One of the simplest(?) ways to achieve that is by using a second, much smaller transformer, with a single secondary winding. Something like a 12V AC, and a 2-3VA rating should be ample. See Figure 1 on this page:
Linear Power Supply Design
The "ground" of that small power supply gets connected to the "-Vcc" pin on that extra connector, and the "positive" of that goes to the "Vd" pin.
One other way to obtain that voltage is with a discrete regulator (like many / most of the IRAUD reference design boards), but that'll need some extra heatsinking.
Fig.33 on page 30 (Q105, Z102, CP101, R114 and R115) over here:
https://www.infineon.com/dgdl/iraudamp7s.pdf?fileId=5546d462533600a40153569addc92bfb
Additionally though, it will also require a third voltage, that "anything between 15 and 25V DC", which is (and here's the key part) referenced to the -VCC rail.
One of the simplest(?) ways to achieve that is by using a second, much smaller transformer, with a single secondary winding. Something like a 12V AC, and a 2-3VA rating should be ample. See Figure 1 on this page:
Linear Power Supply Design
The "ground" of that small power supply gets connected to the "-Vcc" pin on that extra connector, and the "positive" of that goes to the "Vd" pin.
One other way to obtain that voltage is with a discrete regulator (like many / most of the IRAUD reference design boards), but that'll need some extra heatsinking.
Fig.33 on page 30 (Q105, Z102, CP101, R114 and R115) over here:
https://www.infineon.com/dgdl/iraudamp7s.pdf?fileId=5546d462533600a40153569addc92bfb
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So, if I understood well, the driver stage doesn't need a symmetric DC. I'm buying a transformer with two secondaries: one double at 45-0-45V and another single at 15V. Is it suitable for my purposes? For the double secondary I think I will use the V3 universal power supply circuit board. For the single one I can use the rectifier you showed me. So by that output DC I can feed the driver stage. Am I thinking well?
Thanks,
Gaetano.
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