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Class D Switching Power Amplifiers and Power D/A conversion

IR2011 and IRFB4019
IR2011 and IRFB4019
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Old 18th April 2013, 06:06 PM   #1
jmp226 is offline jmp226  United States
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Default IR2011 and IRFB4019

I'm attempting to design a class d amplifier with a half bridge setup. I was wondering if anyone knew if the IR2011 gate driver would be able to drive two IRFB4019 MOSFETS. Thanks
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Old 18th April 2013, 07:06 PM   #2
Tekko is offline Tekko
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It might work but don't expect much above 200kHz with that puny little gate driver, a better option would be the IR2010 with a 3A continous rating.
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Old 18th April 2013, 07:50 PM   #3
Reactance is offline Reactance  South Africa
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Quote:
Originally Posted by jmp226 View Post
I'm attempting to design a class d amplifier with a half bridge setup. I was wondering if anyone knew if the IR2011 gate driver would be able to drive two IRFB4019 MOSFETS. Thanks
For example:
Given: N-Channel MOSFET
VGS = 10V
t (transistion) = 25nsec

Find: Gate drive current, IG.
From the MOSFET manufacturer’s specifications, QG = 50nC at
VGS = 10V. Using IG = QG/t(transition):
IG = QG/t(transition) = 50 x 10-9/25 x 10-9 = 2.0A
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Old 18th April 2013, 09:22 PM   #4
jmp226 is offline jmp226  United States
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thanks for the quick responses!

even though IG comes out to be 2A, would the 3A from the IR2010 still be safe?
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Old 18th April 2013, 09:43 PM   #5
nigelwright7557 is offline nigelwright7557  United Kingdom
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You will have no problems driving the 4019 as it is a low gate charge device.
So long as you don't go silly with operating frequency.

I drove 2 irfp240's in a class d amplifier with no problems.
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Old 19th April 2013, 11:24 AM   #6
manojtm is offline manojtm  India
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Quote:
For example:
Given: N-Channel MOSFET
VGS = 10V
t (transistion) = 25nsec

Find: Gate drive current, IG.
From the MOSFET manufacturer’s specifications, QG = 50nC at
VGS = 10V. Using IG = QG/t(transition):
IG = QG/t(transition) = 50 x 10-9/25 x 10-9 = 2.0A
Hi Reactance,

25ns means 40MHz freq. = 2A I think this is correct.
if your fsw = 400KHz its switching time is 2.5us so it will take only 20mA current

Quote:
I drove 2 irfp240's in a class d amplifier with no problems.
the same i do with IRFP250 no problem

Regards
MANOJ
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Old 19th April 2013, 11:51 AM   #7
Reactance is offline Reactance  South Africa
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Quote:
Originally Posted by manojtm View Post
Hi Reactance,

25ns means 40MHz freq. = 2A I think this is correct.
if your fsw = 400KHz its switching time is 2.5us so it will take only 20mA current



the same i do with IRFP250 no problem

Regards
MANOJ
I would not recommend using IRFP250 for class D designs , if you like me and don't have money (and being a newbie) for expensive switching output mosfets, I would recommend using an IRF540Z as the lowest possible price, most suitable transistor...

IRFP250 are old, and just looking at a few critical parameters;

Total Gate Charge = 120nC vs IRF540Z 63nC
Rds = 0.085Ω vs IRF540Z 0.0265Ω
DSv = 200v
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Old 20th April 2013, 07:26 PM   #8
jmp226 is offline jmp226  United States
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so i have this output stage built, but i have a massive dc offset at the output, about -15V. what am i doing wrong here???
An externally hosted image should be here but it no longer works. Please upload images instead of linking to them to prevent this.
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Old 20th April 2013, 07:28 PM   #9
jmp226 is offline jmp226  United States
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here it is

20130420_150209_zps6b01c702.jpg Photo by Jared_Ogden | Photobucket
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Old 20th April 2013, 07:42 PM   #10
Tekko is offline Tekko
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Simple answer: The COM pin on the IR2011 must connect to the source lead of the low side mosfet, ie the negative rail, in your case -18V and then the IR2011 Vcc need to be 12-15 volts above the negative rail.
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