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12th January 2019, 10:51 PM
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diyAudio Member
Join Date: Oct 2018
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4th-Order filter = Ratios of two 2nd-Order filters?
I recall reading an article that described a 4th-Order filter in terms of two cascaded 2nd-Order filters with specific ratios of f3 and Q.
It looked something like this. The numbers aren't exact, just there to illustrate the point. 4nd-Order Filter with f3 and Q. 2nd-Order Filter 1 f1 = 0.89 * f3 Q1 = .765 * Q 2nd-Order Filter 2 f2 = 1.13 * f3 Q2 = 1.25 * Q Is it really this simple? If so, is there a table of these ratios? |
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