Hi, I'm hoping for a little advice as I'm a rookie at electronics. I'm building an amp (TPA3255 from 3E with PS: LRS-350-48) or at least I would be if the amp were to ever leave the port in China (virus time!!). In the mean time I'm building a chassis vintage style, as in I have a couple of old Bakelite meters and a chickenhead knob so thought it would be fun to make the whole thing look old - just my thing. It would be nice if I could get the meters to work with the amp so my question is does the diagram (excuse bad drawing) make sense? If so what size Shunt would I need (I can't work it out), given I'm running at 48v (maybe a little less 45v?) for the Ammeter? Would I need to add a resistor? Any help appreciated.
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The voltmeter looks ready to go... try it on a 9 volt battery and make sure its OK. The 4ma/12.5k scratched on the back suggests it presents a load of around that value... so no problem there.
50 volts full scale and 4ma work out at 50/0.004 which is 12500
The ammeter has two options and you need the 90 millivolt one. What that really means is that the meter is a 90mv voltmeter in native form or a 240 volt meter with an internal resistor. A moving coil ammeter is simply a voltmeter with a shunt.
So that to me reads as two ranges, 90mv full scale and 240 volt full scale.
So you connect it across a shunt that will give 90 millivolt drop at the maximum current you want it to show at full scale.
So if that is 5 amps then you need a shunt of R=V/I which is 0.090/5 giving 0.018 ohms. Very low as it should be. Try a small piece of hookup wire a few cm long for that.
50 volts full scale and 4ma work out at 50/0.004 which is 12500

The ammeter has two options and you need the 90 millivolt one. What that really means is that the meter is a 90mv voltmeter in native form or a 240 volt meter with an internal resistor. A moving coil ammeter is simply a voltmeter with a shunt.
So that to me reads as two ranges, 90mv full scale and 240 volt full scale.
So you connect it across a shunt that will give 90 millivolt drop at the maximum current you want it to show at full scale.
So if that is 5 amps then you need a shunt of R=V/I which is 0.090/5 giving 0.018 ohms. Very low as it should be. Try a small piece of hookup wire a few cm long for that.
0.18 ohm is available ready made in 5W dissipation, check an electronic parts supplier.
I think we wanted 10 times lower value than that... as a guesstimate of course if we are looking at say 5 amps max current.
And it all depends whether you want something accurately calibrated or just something that moves
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