I'm a bit confused...
Could I use BSC for padding down the tweeter? That way, I could simplify the crossover by using one instead of two resistors... is this possible / a good idea???
Could I use BSC for padding down the tweeter? That way, I could simplify the crossover by using one instead of two resistors... is this possible / a good idea???
BSC is applied to the woofer, then you pad down your tweeter to match the woofer's corrected magnitude. What is it exactly that you want to do ? Could you explain perhaps with a schematic that you have in mind ?
jomor said:BSC is applied to the woofer, then you pad down your tweeter to match the woofer's corrected magnitude. What is it exactly that you want to do ? Could you explain perhaps with a schematic that you have in mind ?
Most of the time. If the XO frequency is low, then it would be done differently.
jomor said:BSC is applied to the woofer, then you pad down your tweeter to match the woofer's corrected magnitude. What is it exactly that you want to do ? Could you explain perhaps with a schematic that you have in mind ?
Yikes.
No wonder I couldn't get my speakers to sound right!
I could never get a correct balance... they either had good, flat bass response or a balanced treble... but not both things 🙄 Silly me.
For the record, the crossover point is 3 KHz. According to the Edge, BSC starts just below this frequency. That's why I thought I may be able to get away with just using one resistor.
I included a diagram of my current crossover. The BSC circuit is ahead of both the tweeter and woofer input. I suppose this is wrong.
So, if I understand correctly, I first need to make sure the woofer is flat right up to the crossover frequency using BSC, and then I pad the tweeter down? Hopefully, this won't be too hard, since I'll be using JustMLS.
🙄
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You may be able to remove the BSC circuit and just make the first inductor in the lowpass larger. Since you have LspCAD, it will be easy to model it and see.
catapult said:You may be able to remove the BSC circuit and just make the first inductor in the lowpass larger. Since you have LspCAD, it will be easy to model it and see.
I assume then that the second circuit is the right one... I think 🙂
If I make the first inductor larger, should I still add a resistor in parallel to it?
Thanks!!!
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