we will get 1/n times the noise power of each resistor.

For example, we we want 1 ohm resistance, we can

parallel 2 pieces of the 2-ohm resistors and get the noise

power half of what we'd get had we used a 1 ohm resistor.

(Assuming 1-ohm and 2-ohm resistors generate equal noise

power).

Is this already well known besides the fact that n parallel

resistors would reduce the tolerance error by n times?

Any opinions?

-Sean