I have a Tent Clock XO2 that Im transplanting from one machine to another. Currently the output is 3.3vpp. The new machine requires a 1.5vpp. Can I use a resistor on the clock output to lower the voltage, without affecting the clocks performance? Thanks in Advance!
Hi,
Don't have Tent Clock XO2 diagram....
I would not use voltage dividers - resistors to lower the output value.
Usually there's a feedback resistor of around 47K on the output buffer / inverter. This resistor value gives 5v pp.
For 1.5V pp I would scale this resistor down to around 14K, or put in parallel to 47K another resistor of around 20K.
Hope this helps.
Who's got the Tent Clock XO2 diagram? Is this caned oscillator?
Regards,
Extreme_Boky
Don't have Tent Clock XO2 diagram....
I would not use voltage dividers - resistors to lower the output value.
Usually there's a feedback resistor of around 47K on the output buffer / inverter. This resistor value gives 5v pp.
For 1.5V pp I would scale this resistor down to around 14K, or put in parallel to 47K another resistor of around 20K.
Hope this helps.
Who's got the Tent Clock XO2 diagram? Is this caned oscillator?
Regards,
Extreme_Boky
audiokid25 said:
Hi
You could consider using a 2:1 step down transformer from minicircuits (T4-6T) or look at www.Scientificonversion.com for alternatives.
By the way, this is the first time I hear from a machine that needs such low voltage. What is the supply voltage of the chip being fed ?
cheers
The supply voltage of the chip its feeding is 3.3v. The chip is a PLL. I managed to lower the voltage of the output by tieing a 56ohm resistor from the output to gnd. It doesnt seem to affect the waveform, but is this going to hurt the clock in the long run?
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