Low Voltage Cutoff circuit needed

Status
Not open for further replies.
I'm building a battery pack, and I need it to become open circuit as soon as it goes below 20v. My battery Is normally at 24v-22v.

What would be the easiest way of achieving this?

I imagine some sort of relay would somehow get switched somehow...😕
 
Nordic said:
Hold on, gotta find it again... I used a derivatie of this circuit for a low battery detector on model aircraft to sound a piezzo...

You should be able to knock one together from the LM311 datasheet..
K, I'll check out the data sheet.... If you have a link to the circuit tho that would be great🙂
 
The problem with a comparator is you need a reference voltage. You could use a switching voltage doubler and then a regulator to get a 20 volt reference. This method has the potential to be very accurate.

Or a 20v zener diode could be used.
 
Check LP2950, it's a micropower 5V regulator. Once you have a 5V supply and reference, a PIC micro with built in comparators may be much more functional than a plain comparator. All this is posible with less than 0.5mA battery drain.
 
[No message]
 

Attachments

  • bat.jpg
    bat.jpg
    5.8 KB · Views: 114
A relay drawing 50mA to 100mA will drain the battery quickly. Not to mention that relais usually close at 75% rated voltage and open below 50%.

The "micropower" way with 5V reference, hysteresis comparator and power MOSFET can do accurate switching without draining the battery.
 
Status
Not open for further replies.