Good afternoon all,
I was looking at a couple of LM317 calculators for R1 and R2.
Question. Is the VOut given in these calculators the voltage drop from the input voltage or the actual voltage output.
The Toroid tranny I have has a 17.8v tap so I was a little confused on what the calculator VOut giving.
Any help would be grateful
Cheers
Brian
I was looking at a couple of LM317 calculators for R1 and R2.
Question. Is the VOut given in these calculators the voltage drop from the input voltage or the actual voltage output.
The Toroid tranny I have has a 17.8v tap so I was a little confused on what the calculator VOut giving.
Any help would be grateful
Cheers
Brian
Good afternoon all,
I was looking at a couple of LM317 calculators for R1 and R2.
Question. Is the VOut given in these calculators the voltage drop from the input voltage or the actual voltage output.
The Toroid tranny I have has a 17.8v tap so I was a little confused on what the calculator VOut giving.
Any help would be grateful
Cheers
Brian
If you can give us a link to the calculator it will be easier to comment!🙂
Sorry - They all seem to be the same.
Here you go.
LM317 / LM338 / LM350 Voltage and Current Regulator Calculators
LM317 Calculator
Thanks
Brian
Here you go.
LM317 / LM338 / LM350 Voltage and Current Regulator Calculators
LM317 Calculator
Thanks
Brian
Hmm, If I understand you correct the Vout is actual output voltage.
And for exapmle if you need Vo = 15V
Then R2 = ( Vout/1.25V - 1 ) * R1 = 12*R1 = 12 *120 = 1.5K
And input voltage must by at least 3V greater the Vout.
So Vin_min = 18V
And for exapmle if you need Vo = 15V
Then R2 = ( Vout/1.25V - 1 ) * R1 = 12*R1 = 12 *120 = 1.5K
And input voltage must by at least 3V greater the Vout.
So Vin_min = 18V
Then what input voltage is it basing the output on?
You can play with the R! and R2 values and get different output voltages. Example if my input was 17.8?
Not trying to be dim, just not getting the concept on how it knows the output without a given input.
thanks
You can play with the R! and R2 values and get different output voltages. Example if my input was 17.8?
Not trying to be dim, just not getting the concept on how it knows the output without a given input.
thanks
Or does the input not matter as long as it is 1.5v above the output?
7.8v to 30v input would give the same output of 6.3?
Thanks
7.8v to 30v input would give the same output of 6.3?
Thanks
As long as Vin is at last 3V above Uout. Input voltage does not matter.
But (Vin - Vout) and load current determine the power that will be dissipate in IC.
Pdis = (Vin_max - Vout_min) * Iload_max.
And without the heatsink power dissipation in IC can not be greater then 1.2W
But (Vin - Vout) and load current determine the power that will be dissipate in IC.
Pdis = (Vin_max - Vout_min) * Iload_max.
And without the heatsink power dissipation in IC can not be greater then 1.2W
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