Wanted to do this passively, DIY. Is it even possible? If yes, do i need resistors of some kind, somewhere?
Thanks.
Thanks.
Are we talking abot the same music track??
And why would you??
Mono means just ONE channel. You can play it on a 15 channel surround system, but you will have every speaker playing the
exact same ting. Maybe I misunderstand you, but I can´t seem to find a reason for you question 😉
And why would you??
Mono means just ONE channel. You can play it on a 15 channel surround system, but you will have every speaker playing the
exact same ting. Maybe I misunderstand you, but I can´t seem to find a reason for you question 😉
You can sum a stereo signal (two channels) into a mono signal (one channel).
Please supply more information if that is not your requirement.
Please supply more information if that is not your requirement.
Technically, yes it is possible. Just binding the wire together with the right polarity (ground with ground, then let each other side be your left and right)
As for the usefullness, well, you decide / you know what you want…
As for the usefullness, well, you decide / you know what you want…
Mono music from any source and voice from microphone added. Played back on a stereo system. It can be done with a passive or an active mixer. In the simplest case just a couple of resistors.
Just use an RCA Y connector. Mono input RCA jack to two RCA plugs. Also most legacy audio amps and receivers like from the 70s and 80s have a mono switch which will do what you want with a single input.
Newer home theater AV receivers have DSP modes that can simulate stereo from a mono source. But there still is no substitute for a true stereo recording.
Newer home theater AV receivers have DSP modes that can simulate stereo from a mono source. But there still is no substitute for a true stereo recording.
Technically, two different mono signals played simultaneously (one per channel) ARE one stereo signal.
Many early stereo recordings were made in a similar way.
But if you add them together first, and input the mono result into both channels, you just have virtual center mono,
which is inferior to true one channel/one speaker mono, due to the inherent acoustical problems.
Are you trying to blend separate channels of a voice and an instrument, for example?
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With phase shifting filters you can mimic pseudo-stereo out of mono.
But from two different sources? I imagine heavy metal hard rock (mono) driven to the left, and Beethoven's Eroica (mono) to the right.
Ehmm...
But from two different sources? I imagine heavy metal hard rock (mono) driven to the left, and Beethoven's Eroica (mono) to the right.
Ehmm...
This is done with a pan-pot, or for two signals, two pan-pots. Active versions are more flexible, but its possible passive too (there was a recent question on this very subject IIRC).
[ Ah, no that was about combining two stereo signals in fact... ]
[ Ah, no that was about combining two stereo signals in fact... ]
Hi,
There are op-map preamp circuits to do this.
Check this out Article based on "Electronics Australia", Vol. 46, April, 1984"
How to create stereo from mono signal
There are op-map preamp circuits to do this.
Check this out Article based on "Electronics Australia", Vol. 46, April, 1984"
How to create stereo from mono signal
I don't either. 🙂
It's irritating when a poster posts something like this and doesn't come back to elaborate. (The query could be interpreted in multiple ways.)
Dave.
Sure, you could use a dual-gang potentiometer (I suggest 100K linear taper) to get
I'll let other members have the pleasure of drawing out the circuit schematic, it's pretty simple.
- OUTPUT_left = (rot% * INPUT_a) + ((100 - rot%) * INPUT_b)
- OUTPUT_right = ((100 - rot%) * INPUT_a) + (rot% * INPUT_b)
- when rot = 100% you get {OUTPUT_left = INPUT_a} and you get {OUTPUT_right = INPUT_b}
- when rot = 0% you get {OUTPUT_left = INPUT_b} and you get {OUTPUT_right = INPUT_a}
- when rot = 50% you get the average of INPUT_a and INPUT_b on both left and right OUTPUTS
- when rot = 25% you get {left = (25% * a) + (75% * b)} and {right = (75% * a) + (25% * b)}
I'll let other members have the pleasure of drawing out the circuit schematic, it's pretty simple.
This can be addressed by using two beffer op-amp for input, use resistors at output to cobine both (simple way) or use another opamp as adder circuit,
Many circuits(schematics) are available online, search for "Mono to Stereo circuit" or "op-amp mixer circuit" or "op-amp adder circuit"
This is wonderful
Thread-starter obviously has no clue what mono or stereo really means and you hit the poor fellow with math model of possible interpretation oh his "question". Delightful !
Thank you Mark, you made my day
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In Stereo , Vocals, Intstruments are divided into two channels for eg. Drums in one channel, Keyboard in another, Vocal in both. Playing Mono is two speakers is not stereo.
If you have stereo amplifier when you connect mono input chances are there you will hear from one side not other (depending on cable & connector).
If you have two mono outputs connect these to L and R inputs of amplifer.. thats it .
Err, not unless the sources have significant output impedance, otherwise they will drive each other. Normally you would put 1k or so in series with each before the junction.