Could someone help me out with some Instantaneous Voltage calculations please.
I need to calculate the value of the resultant waveform at 45deg 120deg & 240deg that includes a third harmonic content of 20v.
Vmax is 200V, third harmonic amplitude is 20v
I know that to find the instantaneous voltage the calculation is:
e = Vmax sin0
So
e = 200 x sin 45 = 141.4V
e = 200 x sin 120 = 173.2V
e = 200 x sin 240 = -173.2V
Do I just ADD the 20v to each result to include the third harmonic amplitude or is there more to it?
Cheers
I need to calculate the value of the resultant waveform at 45deg 120deg & 240deg that includes a third harmonic content of 20v.
Vmax is 200V, third harmonic amplitude is 20v
I know that to find the instantaneous voltage the calculation is:
e = Vmax sin0
So
e = 200 x sin 45 = 141.4V
e = 200 x sin 120 = 173.2V
e = 200 x sin 240 = -173.2V
Do I just ADD the 20v to each result to include the third harmonic amplitude or is there more to it?
Cheers