How does the "Jewel thief" work?

Does it really work?? Or to say better does component looses not exceed energy gained
It does not GAIN energy.

It transforms the voltage.

If the voltage gain were exactly 2times and the efficiency were 100%, then the input current would be 2times the output current.

If the efficiency is 50%, then the input current would be 4times the output current.
The three example efficiencies are from 57% to 79% (wiki link), realising a current drain of 3.5times for the BC549 to 2.5times for the ZTX650, if the input voltage is exactly half the output voltage.
If the high current drain on the battery results in a lower input voltage, then the current drains becomes even higher.
A very good way to completely discharge an already low battery.
 
Last edited:

Mark Johnson

Member
Paid Member
2011-05-27 3:27 pm
Silicon Valley
Google offered up links to LTSPICE simulations of the Joule Thief. I grabbed one, cranked down the battery voltage to 0.6V, and ran it with a white LED whose forward voltage is 3.6V according to its datasheet (Nichia NSPW500BS). Thankfully the simulation agrees with real-life results on the bench: an 0.6V battery cell indeed can flash a 3.6 volt LED by means of a Joule Thief.

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