it is not working as you may have supposed
simple, maybe a bit experimental mosfet one burns one resistor and I don't know why
can this be caused by output mosfets failure??
output voltage is ~3V
please help me wiser ones
if you want to avoid wasting money in destructed mosfets, use Zener protection diodes. One between emitter of Q10 and output. Another onebetwwen the output and the emitter of Q? (PNP complementary to Q10). You can use Zener voltage about 2 volts lower than the max rated VGS of the IRF mosfets.
If you destroy zener diodes it costs less than the IRF...
Check R24, R25 for open as well as the 0.22R resistors. If you have that much across the 470R resistor, Q10 and it's compliment are either on or could be in reverse E-B breakdown. I'm fairly sure you will find a few transistors shorted. An open PCB connection could change things though.
one more question: what will be minimal zener current thru 0.5W 47V zener diode? I have less than 1mA I'm affraid.
BTW: all I wanted from this project was to keep output at low feedback with minimal number of stages. I used inverting mode making summing junction the slowest part of everything by means of pole-zero compensation.
This should work nice in terms of low TIM and little interference with speaker back EMF, especially HF component of this signal. What do you think?
that's why I use for VAS separate transformer, 2x1000u caps filtering +-74V rail, regulated down to +-53 by lm317/337 and filterd by 2x10u caps.
Making it is so inexpensive and simple, and makes amplifier "don't worry" about PSRR aside from efficiency issue.
Thank you for suggestion, time will tell if it is going to have low noise or not.