Can I use fluorecent choke (36W lamp )as PSU choke ? It is much cheaper and has DC resistant of ~ 80 Ohms.. I do not have a LCR meter, donno what is the Henry value.. any experience can share ? 😛
Measured some of them, 0.3 - 1.5 H, depends on type.
You need to measure your choke, then use PSU Designer.
They can be used for low-power loads (preamps, tube gear, etc.).
You need to measure your choke, then use PSU Designer.
They can be used for low-power loads (preamps, tube gear, etc.).
I used a 250W mercury vapour ballast (choke) for a CLC filter once and it worked fine even though it was not designed for DC. The henry value can be calculated by knowing the details of the lamp it drives.
Low loss types have a lower DC resistance and more inductance, for comparison @240V 36W, a standard ballast has a 40 ohm DC resistance and a low loss type has a 23 ohm DC resistance.
80 ohms seems like a lot of DC resistance even if the ballast were designed for a 277V supply it should have a similar or slightly lower DC resistance than the 240V 50Hz ballasts I measured.
Low loss types have a lower DC resistance and more inductance, for comparison @240V 36W, a standard ballast has a 40 ohm DC resistance and a low loss type has a 23 ohm DC resistance.
80 ohms seems like a lot of DC resistance even if the ballast were designed for a 277V supply it should have a similar or slightly lower DC resistance than the 240V 50Hz ballasts I measured.
DC will reduce the inductance, as these chokes won't have an air gap. You need to measure it with DC present, or just build a PSU and measure the output. What you can't do is measure the inductance at zero DC and then simulate a circuit assuming it retains that inductance.
They have distributed high reluctance sections, because they have to operate as power inductors, and are not allowed to saturate significantly within their operating range.DC will reduce the inductance, as these chokes won't have an air gap. You need to measure it with DC present, or just build a PSU and measure the output. What you can't do is measure the inductance at zero DC and then simulate a circuit assuming it retains that inductance.
The fact that they operate in AC changes nothing.
The parameter to take into consideration for saturation is the instantaneous current.
I just measured a 15W ballast (for 230V). The (cold) DC resistance is 56 ohm, and the inductance is 1.56H (under small signal; at the nominal current, it is normally higher).
The maximum rms current is 0.33A --> 468mA instantaneous.
It could be used up to that current in DC, except it will overheat.
1.5H is not much, but it can be useful tough, and it could be parallel-tuned for 100Hz.
1.5H is not much, but it can be useful tough, and it could be parallel-tuned for 100Hz.
Does it mean we can parallel the choke and ideally it should behave as follow..
50Ohms ( 1.5H ) || 50 Ohms (1.5H) = 25Ohms (3H)
and the max allowable current will double 0.33 A x 2 = 0.66A ?
thanks for the point out. I have mistakenly tot inductor & capacitor behave the same. In fact they aren't
Does it mean we can parallel the choke and ideally it should behave as follow..
50Ohms ( 1.5H ) || 50 Ohms (1.5H) = 25Ohms (3H)
and the max allowable current will double 0.33 A x 2 = 0.66A ?
No, I mean you can parallel it with a 1.69µF capacitor to increase the rejection at 100Hz (~30dB), provided you already have a conventional filter to remove higher harmonics.
actually,is enough1.5H is not much, but it can be useful tough, and it could be parallel-tuned for 100Hz.
i did simulations of same capacity used in multiple CLC filter, and compared to single choke 10H vs two 1H
/hammond has low current types at hi inductance, i was curious what is better- if one heavy or two smaller chokes/
believe or not, the two choke was better, and this has decreasing ripple with increasing current. (second one starts kickin in)
but single type had increasing ripple with
36W lamp choke /i have no LCmeter at home/ seems has ~0,94H 2,7µF paratune
(according to lamp datasheets 100V@0,43A)
18W lamp should have ~1,5H,
58W 0,57H
difference between currents are not high, therefore 18W seems best
also tried primary of 230 transformer as choke, but it failed-no filtering at all(obviously), but these puppies works for me
I just measured a 15W ballast (for 230V). The (cold) DC resistance is 56 ohm, and the inductance is 1.56H (under small signal; at the nominal current, it is normally higher).
The maximum rms current is 0.33A --> 468mA instantaneous.
Strange. I measured the my choke by LCR meter, this is the result:
DC resistant of ~ 59 Ohms and the inductance is 115 mH
UFOlder.ru ?????????? ??????? ??????, ???????? ??????, ????? ???????.
An externally hosted image should be here but it was not working when we last tested it.
Then, either your LCR meter does not work, or your ballast is damaged:Strange. I measured the my choke by LCR meter, this is the result:
DC resistant of ~ 59 Ohms and the inductance is 115 mH
UFOlder.ru ?????????? ??????? ??????, ???????? ??????, ????? ???????.
An externally hosted image should be here but it was not working when we last tested it.
A fluorescent tube drops around ~100V; the reactance of your ballast is 0.115*6.28*50=36Ω, which results in a total impedance of 69Ω.
The current would be 130/69=1.88A, thus a power of ~188W in the tube: not very realistic
testing few days tubeheadamp (ECC802+6L6), it is dead quiet, no hum
CLC+CRC supply with this 36W choke, AC filaments.
Beyers DT990 250ohm , TASCAM US200
satisfied very much
CLC+CRC supply with this 36W choke, AC filaments.
Beyers DT990 250ohm , TASCAM US200
satisfied very much
Those chokes can be very usable in a PS. As allready mentioned, they are up to about 1,5H. If needed, you can use similar units in parallel/serial connections. I had the best results with "old" steel encased types (Philips) that have low dc-losses, low strayfields and no audible noise. If you want to know the exact inductance you must measure them in the actual circuit with the actual dc current applied (LCR meter readings may vary wildly and are most often worse than a educated guess).
Does it mean we can parallel the choke and ideally it should behave as follow..
50Ohms ( 1.5H ) || 50 Ohms (1.5H) = 25Ohms (3H)
and the max allowable current will double 0.33 A x 2 = 0.66A ?
2 x 50ohm 1,5H 0,33A in parallel = 25ohm 0,75H 0,66A
2 x 50ohm 1,5H 0,33A in serial = 100ohm 3H 0,33A
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