I have an unbalanced miniDSP that can do 0.9V RMS MAX output. I have an ep4000 in bridged mono mode and an lms-r 15" set up as a 4 ohm load.

which math is correct:

4 ohm bridged mode:

1950 W = (V*2*50)^2/4

V = 0.88 V

When bridging an amplifier, the voltage gets doubled, which is where the *2 comes from. So from this math the ep2500/4000 only needs 0.88V to reach it's max output on 4 ohm bridged. The measured power value is from here Measuring Amplifiers

The *50 is from the 34 dB gain of the ep4000 amplifier. The /4 is from the 4 ohm load.

OR

1950 W = (V*50)^2/4

V = 1.73 V

where bridging the amp doesn't double the voltage.

Which way is the correct way?

Thanks

which math is correct:

4 ohm bridged mode:

1950 W = (V*2*50)^2/4

V = 0.88 V

When bridging an amplifier, the voltage gets doubled, which is where the *2 comes from. So from this math the ep2500/4000 only needs 0.88V to reach it's max output on 4 ohm bridged. The measured power value is from here Measuring Amplifiers

The *50 is from the 34 dB gain of the ep4000 amplifier. The /4 is from the 4 ohm load.

OR

1950 W = (V*50)^2/4

V = 1.73 V

where bridging the amp doesn't double the voltage.

Which way is the correct way?

Thanks

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