Diy 500w budget amplifier

Hello, im making an irs2092s based amplifier which im hoping will power my 4 ohm subwoofer with 500w, maybe 750 if I'm lucky.
My amp uses two 12v 30a smps supplies each wired to a "400w" rated 12v to 65v buck boost converter. These two isolated 65v stepups supply the irs2092s with +-65v (120vdc)
I measured the current draw on one of the power supplies whole playing at full volume, measuring a current draw of 2.8A at 12v.
I'm not entirely sure how many watts I'm outputing, based off the current draw mentioned is it likely that I'm getting 500w output?
Is this the right equation:
2.8 A x 60v = 170w (so one step up is putting out 170w?)
Efficiency of stepup is probably around 90%
90% x 170 = 150w
There is two stepups going into the irs2092s so:
150w + 150w = 300w
Am I right? Is the irs2092s only putting out 300w? Not considering losses from the irs2092s
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If I understand your post correctly, one of the power supplies is supplying 2.8 * 12 = 33.6W.
Your amplifier will be 50% efficient at most if Class A, so lets assume 16W.

The two amplifiers in total will be 32W.

Or am I misunderstanding something?
 
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Also note that it is not two amplifiers.
Two isolated power supplies each outputing 12v are individually wired to their own 12v to 60v stepups
This means there is now two isolated 60v supplies available
The two 60v supplies are wired together at their outputs to give +60v, 0v and -60v which goes to one irs2092s
 
“Playing at full volume” with music is probably NOT putting out anywhere near full average power. Even when distortion starts. Play a sine wave and it will draw A LOT more. Speaker may fry - you would need a dummy load to do this safely.