i dont understand what you are asking the unit is an ic amp up to about0.6 amps then switches on the output transistors nothing new here
That is maxwell bridge.
If C1*L1=Z1*Z3,that will balance.
but I don't know why balance can get rid of crossover distortion.
If C1*L1=Z1*Z3,that will balance.
but I don't know why balance can get rid of crossover distortion.
That doesn't make sense. The units of C*L are not the same as the units of Z1*Z3 which are R*R. It should be L/C = R*R, or L=RRC. Where did you get this from? It seems to me you should be considering Z1, Z2, Z3, and Z4. C1 is just part of a shunt Zobel network, and L1 is just a series inductance to the load, both being present for stability reasons. Neither is part of any bridge.
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There's a lot new here, in the sense that the bridge components are calculated such that the output stage distortion is eliminated.i dont understand what you are asking the unit is an ic amp up to about0.6 amps then switches on the output transistors nothing new here
QUAD current dumping concept.
Jan
Attachments
Then look up Current Dumping Audio Amplifier, P.J. Walker & M.P. Albison, Wireless World, December 1975. But the correct equation here is (Z4*Z2)/(Z1*Z3) = 1, or L=RRC. Not your version: you have both the wrong capacitor and the wrong inductor in yours.
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In the real 405 circuit, Z3=47R, Z1=500R, and the op-amp is inverting.
You still haven't answered where you are getting all this from.
You still haven't answered where you are getting all this from.
Still haven't answered that question. Where did you get your original circuit from? and that equation?
Still haven't answered that question. Where did you get your original circuit from? and that equation?
The equation is from his paper.
And the circuit diagram is modified from the original circuit diagram.
No it isn't. You gave C1*L1=Z1*Z. Where did you get that from?The equation is from his paper.
Modified why?And the circuit diagram is modified from the original circuit diagram.
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