I don't want to be silly but my first reaction is that if it is a co-ax the cross over is probably intergral with the unit. For a start can you tell us how many ternimals does the speaker have? If its only a pair. i.e. one positive and one negative then that suggests there is an internal cross over. Put up the manufacture's name might help and post when people in that part of the world are surfing.
If it does need an external xover then the specs suggest a shelving network is needed to drop the tweeter down to the level of the woofer and then something around 2kilo heretz would look promising.
If it does need an external xover then the specs suggest a shelving network is needed to drop the tweeter down to the level of the woofer and then something around 2kilo heretz would look promising.
Hey jonathan,
The speaker is P Audio. - BM-10CXA
http://www.paacoustic.com/Product_Detail.asp?CatalogID=0108&ProductID=BM-10CXA
As far as i know the crossover is not intergral.
From the pic you can see the 2 terminals for the woofer and the two terminals for the hf unit are at the base.
Thanks.
The speaker is P Audio. - BM-10CXA
http://www.paacoustic.com/Product_Detail.asp?CatalogID=0108&ProductID=BM-10CXA
As far as i know the crossover is not intergral.
From the pic you can see the 2 terminals for the woofer and the two terminals for the hf unit are at the base.
Thanks.
Hi, I think you will have to experiment a bit here
If you do as Jonathan suggested - to cut midrange at 2Khz with a single coil - you will probably get a delayed reaction because of following peak, and afterwords get a little higher suiteable crossoverpint - then simly find a condensator to match - a simle case of "try and error"
I have been interested in this thing too, so let us know how it goes further.
If you do as Jonathan suggested - to cut midrange at 2Khz with a single coil - you will probably get a delayed reaction because of following peak, and afterwords get a little higher suiteable crossoverpint - then simly find a condensator to match - a simle case of "try and error"
I have been interested in this thing too, so let us know how it goes further.
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