Is wiring two X1000's in series the same as bridging them? if not please explain what the difference is.
I also understand how 2 standard mono channels (with a +ve and ground output) can be bridged together to provide double the peak to peak voltage and double the current (ie. 4 times the power) using the +ve outputs of 2 such amps amplifying an in-phase and out-of-phase signal to create a +ve and -ve output to the speaker.
What i dont understand is how the increased peak to peak voltage is achieved when there is already a +ve and -ve (ie. balanced) output (ie. a -ve output instead of a ground output) such as in the X1000. The literature says you need floating inputs such as are created by the array interface so I know it is to do with the floating inputs and i have been reading the X1000 back engineering thread here which is kinda sinking in but mostly going over my head
I understand that the signals are not always automatically referenced to ground but instead sometimes to some other figure that is cancelled at the outputs. So more accurately, i guess the question should be this...... in an array of X1000's can the voltage swing of the array exceed the voltage swing of a single X1000 ie. ~145V between +ve and -ve outputs? If so, where does the extra voltage come from / or more correctly how are the amps wired to each other to produce it?
In the interest of keeping things simple, when using 2 X1000's in series / bridging them, how are the inputs and outputs from each amp connected to each of the inputs and outputs of the other amp to achieve this? ie. how do u wire two X1000's in series or bridge two X1000's?
I also understand how 2 standard mono channels (with a +ve and ground output) can be bridged together to provide double the peak to peak voltage and double the current (ie. 4 times the power) using the +ve outputs of 2 such amps amplifying an in-phase and out-of-phase signal to create a +ve and -ve output to the speaker.
What i dont understand is how the increased peak to peak voltage is achieved when there is already a +ve and -ve (ie. balanced) output (ie. a -ve output instead of a ground output) such as in the X1000. The literature says you need floating inputs such as are created by the array interface so I know it is to do with the floating inputs and i have been reading the X1000 back engineering thread here which is kinda sinking in but mostly going over my head
I understand that the signals are not always automatically referenced to ground but instead sometimes to some other figure that is cancelled at the outputs. So more accurately, i guess the question should be this...... in an array of X1000's can the voltage swing of the array exceed the voltage swing of a single X1000 ie. ~145V between +ve and -ve outputs? If so, where does the extra voltage come from / or more correctly how are the amps wired to each other to produce it?In the interest of keeping things simple, when using 2 X1000's in series / bridging them, how are the inputs and outputs from each amp connected to each of the inputs and outputs of the other amp to achieve this? ie. how do u wire two X1000's in series or bridge two X1000's?