This link gives you an idea what you do.
http://www.audioasylum.com/forums/HUG/messages/4151.html
To give an example.
Suppose you have a 10 inch speaker that is flat down to 30 Hz in a 3 cubic foot box.
Normally, you would build a 3 cubic foot box and use a 3" diameter port that is 4.7 inches long. Alternatively, you could use two 2" diameter ports the same length. The box tuning would be identical.
In a double chamber reflex, you would build your box identically to the normal single chamber-with 2 differences.
First, the double chamber box will have a partition that divides the box into two unequal chambers. The smaller is 1 cubic foot, the larger 2 cubic foot.
The woofer is mounted in the bigger chamber.
Instead of one 3" diameter port, we use the equivalent of two 2" diameter ports. However, one 2" port vents the larger chamber to the outside, the other vents the smaller chamber to the outside.
Important-there is THIRD vent, always identical in size to the other two. That is put into the partition between the two chambers, on the inside of the box. So the two chambers have a 2" diameter vent 4.7" long between them.
So when we view this speaker, we see two 2" diameter vents. We do not see the one on the inside of the enclosure.
You can do the equivalent in any vented speaker. Just make sure the ratio between the larger box and smaller box is 2 to 1.
According to Weems, if a speaker works well in a simple vented box, it will work just as well, with the same cutoff, in a double chamber box. If you want to be persnickety, you can make the double chamber box slightly larger to acomodate the internal partition and the vent. Usually, it won't make too much difference if you do.
I hope I have explained this well.
The normal way this is drawn is a 3 foot tall enclosure, the larger chamber with the woofer on the bottom, the smaller chamber on the top. The vents are on the front, one on the top, the second one on the bottom.
I will be glad to answer any questions if this is not clear.