Simpleton said:
a) I read on and article from a 50's magazine that the gain of a pentode is G=gm x Ra
Approximately. For RL << Rp, it's pretty close.
For a simple pentode stage, with gm=0.9mA/V and Ra=56KOhm, the gain goes to around 50X! Isn't this too much? (the pentode's internal anode resistence is around 2MOhm)
Nope- works just right! Consider what Gm is to begin with: a change in plate current for a change in grid voltage. (Sidenote: ohms are volts divided by amps (R = V/I); conductance is the reciprocal of ohms, or I/V. Gain is rated in terms of output figure over input figure, in the case of a voltage-controlled device like a pentode, you have a change in output current divided by a change in grid voltage - because they aren't directly connected, we tack on a "trans" and name it "trans-conductance".

)
Now, considering the plate resistance is up at 2 megs, we can ignore it altogether. That means a change in grid voltage of maybe 0.1V will cause a change in plate current of 0.1 * 900 x 10^-6 = 90 x 10^-6, 90 microamperes. Across a 220k resistor (current must be quite low for a mere 900umhos, so I'm assuming a large RL) this causes a change of V = IR = 19.8 volts, for a total gain of almost 200!
Indeed, into a constant current source, where Rp dominates, rather than RL, mu (amplification factor) is equal to Gm * Rp, or for your example, µ = 1800. Compare that to a single triode with 100 tops!
Typical gain stages (look at the GE datasheet for 6AU6 and other popular pentodes) quote gain in the range of 100 to 500.
b) How can i use a nice 0A3, which i happen to have 2, as a power on indicator light? I know i could use a simple neon bulb, etc, but the 0A3 is sooo cute
Hehe. One, you can always put a regulated supply in your amp - at 90V (75? I forget), it would work for screen supply for some late-era sweep tubes (6LQ6, et al), two in series (uh, 150/180V) for powering a preamp or regular (6L6, EL34, etc.) screens, or use one as voltage reference for a pass regulator of any voltage. If you can't squeeze that in, you can simply add a series resistor and connect it to any power supply, AC or DC. You'll need about 1-1.5k (2-5W) per tube to run from 120VAC, or 5-10k from +300V. Don't parallel them; like LEDs and zeners, one will hog all the current.
Tim