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Old 18th September 2012, 05:45 PM   #1181
Takaji is offline Takaji  Canada
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Originally Posted by BrianDonegan View Post
Sharing the SE outputs between a headphones and a high-impedance load (amplifier) if the way to go.
Just curious though; if I'm already using the SE outputs on the IVY board to drive a pair of speakers, would I still tap into the SE output for the headphone jack? Would this affect the output to the speakers, since the signal is being shared between two sources?
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Old 5th November 2012, 03:55 PM   #1182
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Will the BIII board be on the market concurrently with BIIISE? If so, what is the ETA of the next batch?
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Old 5th November 2012, 04:06 PM   #1183
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Will the BIII board be on the market concurrently with BIIISE? If so, what is the ETA of the next batch?
It will, but it will be a month or two before more are available. I am working on shrinking that time frame, however.
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Old 6th November 2012, 05:24 PM   #1184
c12mech is offline c12mech  United States
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I am finishing one of these now. I need to have an LED indicating power on. I have used both a Placid and Placid BP for power supplies. Can I just tap in to the test points on the Placid for the led? That should not hurt anything right? I know it's a dumb question but I had to ask before I mess something up.
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Old 7th November 2012, 08:34 AM   #1185
Corpius is offline Corpius  Netherlands
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Yes that's a possibility, but do use a resistor in series to limit the current. You can also use the lock LED, but when there is no lock (sources are off) it will not indicate that the DAC is powered.

EDIT: and make sure that the shunted current is still around 50 mA when you power the LED directly from the Placid.
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Old 7th November 2012, 12:19 PM   #1186
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Originally Posted by c12mech View Post
I am finishing one of these now. I need to have an LED indicating power on. I have used both a Placid and Placid BP for power supplies. Can I just tap in to the test points on the Placid for the led? That should not hurt anything right? I know it's a dumb question but I had to ask before I mess something up.
Just use a resistor from the Placid output. Typically (depending on LED), shoot for 12-15mA, so

R = .012/[Your output voltage]

As Corpius pointed out, readjust the shunt current when you are done.
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Old 8th November 2012, 12:03 AM   #1187
c12mech is offline c12mech  United States
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Thanks guys.

I think I will go with Brian's suggestion as it will be the easiest to do. There will be a power LED along with a lock LED on the front panel.
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Old 22nd November 2012, 06:41 PM   #1188
c12mech is offline c12mech  United States
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I have everything together and now the selector LED's do not work. I have tried different LED's with no luck. I get the lock with each input but no indicator. Nothing I have tried has worked. Any ideas?
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Old 23rd November 2012, 03:14 PM   #1189
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Any ideas?
Double check you have them the right way round?
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Old 23rd November 2012, 05:14 PM   #1190
c12mech is offline c12mech  United States
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That was the first thing I checked. It's not the LED's themselves it's that I have no voltage going to them. I switched to each input and none of them have power going to the LED's. I did check that there was voltage getting to the selector switch and there is 3.4v from pin 4 to ground and none anywhere else on the board. Has anyone else had this problem or is it just me?
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