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| Tubes / Valves All about our sweet vacuum tubes :) Threads about Musical Instrument Amps of all kinds should be in the Instruments & Amps forum |
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#1 |
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diyAudio Member
Join Date: Jan 2005
Location: Chicago
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I am trying to calculate the ra for a triode strapped EF86 for a parafeed linestage. My OPTs are 15K:500, so I am hoping this will work -- several NOS Amperexes just dropped into my lap, so it seems like a good place to use them.
Anyhow, Here is a EF86 datasheet: http://www.mif.pg.gda.pl/homepages/f...030/e/EF86.pdf Triode strapped, mu is about 25. It looks to me like gm is .004 which would put ra at 12500. Does this seem right? |
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#2 |
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diyAudio Member
Join Date: Apr 2001
Location: Milwaukee, Wisconsin
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Well, I hope someone can verify this because I'm taking an educated guess. At Va of 150V the tube draws 2ma. At 183Va the tube draws 4ma. Rp should be 33/.002 or 16500 ohms.
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#3 |
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diyAudio Member
Join Date: Jun 2005
Location: San Diego, CA
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You would need to specify your operting conditions for a more acurate answer...Since these a VARIABLES...not constants...
For example: At 150v at the plate, -3V bias with 2 mA of DC current.... Your Plate resistance would be 18.75k ohms.... mu would be roughly 34.... The gm would be roughly 1.8 mA/v .... Chris |
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#4 |
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diyAudio Member
Join Date: Jan 2005
Location: Chicago
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Hmmm. The triode curves look like with 150V on the plate, changing Vg from -3 to -2 results in a change in Ia from 2mA to 4.2mA. mu does look to be higher than I though (using a CCS on the plate ~ 37), so other than some sloppy chart reading, I am at least doing the calculation correctly. This leads to ra = 17K or so.
Anyone care to venture an opinion on whether 15K:500 parafeed transformers will work here, or if using them at 30K:1K is a good idea ... or should I just use my usual answer at times like this which is to use the 5842 wunder-tube ... |
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#5 |
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diyAudio Member
Join Date: Oct 2003
Location: Finger Lakes, NY
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dsavitsk, the plate resistance at any operating point is the slope of the plate curve there. (Really, it's the inverse of the slope: ra = dV/dI) I've draw a line that is tangent to the -4V line at roughly 225V@5mA. The slope of the line is the (change in voltage) / (change in current) = (250V-160V)/6mA = 15k
-- Dave
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January 20, 2009: Bush's last day |
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#6 | |
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diyAudio Member
Join Date: Apr 2004
Location: Plainsboro, NJ
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Quote:
Use the 5842. Experience says 3X Rp is in order for the load. Don't forget that primary inductance is important.
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Eli D. |
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#7 | |
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diyAudio Member
Join Date: Jan 2005
Location: Chicago
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Quote:
There is a tool for working through some of this at http://www.siteswithstyle.com/voltse...afeed_fun.html so maybe grinding through the math is the answer here. |
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#8 | |
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diyAudio Member
Join Date: Apr 2004
Location: Plainsboro, NJ
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Quote:
The load the tube "sees" is the parallel combination of the CCS and the load presented by the trafo. Obviously, the trafo is dominant. Inductive reactance (Xl) = 2 pi F L If the primary's inductance is too small, LF info. has a low impedance path around the load reflected from the secondary.
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Eli D. |
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