grid impedence of paralleled tubes in push pull

nhuwar · 13th January 2007, 11:35 PM

When connecting the tubes in parallel is the impedence z\number of tubes or does it not change the z. Is there a formula for finding this?

Also push pull is the input signal to the 2 sides 180 degrees from each other but twice the signal input?

Miles Prower · 14th January 2007, 12:24 AM

Quote:

Originally posted by nhuwar
When connecting the tubes in parallel is the impedence z\number of tubes or does it not change the z. Is there a formula for finding this?

Paralleling reduces impedance. It also increases capacitance.

Quote:

Also push pull is the input signal to the 2 sides 180 degrees from each other but twice the signal input?

Yes

nhuwar · 14th January 2007, 12:37 AM

I guess what i'm really getting at is how do you figuare the z because I was thinking it's not just finding the capacitance reactance of the grid at the lowst or highest frequency.

13th January 2007, 11:35 PM	#1
nhuwar diyAudio Member Join Date: Jan 2007 Location: Tomball Texas	grid impedence of paralleled tubes in push pull When connecting the tubes in parallel is the impedence z\number of tubes or does it not change the z. Is there a formula for finding this? Also push pull is the input signal to the 2 sides 180 degrees from each other but twice the signal input?

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14th January 2007, 12:37 AM	#3
nhuwar diyAudio Member Join Date: Jan 2007 Location: Tomball Texas	I guess what i'm really getting at is how do you figuare the z because I was thinking it's not just finding the capacitance reactance of the grid at the lowst or highest frequency.

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