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#1 |
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diyAudio Member
Join Date: Apr 2004
Location: Philly
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I am working on a P-P 7189 amp, class A (probably around 275v/10k load... haven't decided yet) and I want to rig up a simple-as-possible CCS phase inverter. Since the drive requirements for the 7189's are so low, a 12ax7 LTP should be fine to drive them from a line level input, so I don't have a driver stage to return feedback to. I drew up this inverter and wanted someone to check it out. I returned the feedback to the non-inverting grid. Simulations looked OK, but I want some opinions/ other options options before I breadboard.
Thanx
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#2 |
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diyAudio Member
Join Date: Nov 2002
Location: sg
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i always find 12ax7s failling to sound dynamic when forced to swing more than a couple volts. why not try some tube like the 5687 that is more fit for this role?
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#3 | |
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diyAudio Member
Join Date: Apr 2004
Location: Philly
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Quote:
Only because I have a pile of 12ax7's around. If the design ends up being sound, I'll probably redesign around a better tube. Does the circuit itself look good? I could always readjust the plate resistors and CCS for a different tube later.
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#4 | |
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diyAudio Moderator Emeritus
Join Date: Jan 2004
Location: Jakarta
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Quote:
The second method can be achieved by connecting the grounded grid to a potential divider from B+ to ground, with a cap of ~0.33uF from that grid to ground, in series with your feedback resistor (which can be smaller than you have shown here - say 1k). You need a 1Meg resistor between the grids, instead of from grid of the left half of the LTP to ground. It can also be achieved by dierect coupling from the previous stage (if there is one). You will still need the bypass cap and feedback resistor on the grounded grid and the 1Meg resistor between the grids. |
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#5 |
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diyAudio Member
Join Date: Jul 2005
Location: Madrid, Spain
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Hello.
See if that idea meay be usefull to you. You nay reduce considerably NFB. Best regards |
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#6 |
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diyAudio Member
Join Date: Jul 2005
Location: Madrid, Spain
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See if that one is usefull to you:
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#7 | |||
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diyAudio Member
Join Date: Apr 2004
Location: Philly
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Quote:
Quote:
Quote:
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#8 | |
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diyAudio Member
Join Date: Apr 2004
Location: Philly
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Quote:
That looks pretty simple. What is the theory behind biasing the transistor to the junction of the 1M resistors? Do I need to generate a negative rail there as well?
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#9 |
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diyAudio Member
Join Date: Jul 2005
Location: Madrid, Spain
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This diff pair can work with only one input.
The 1M resistors are error detector and at same time they pull the transistor on wich provide current to the diff pair. See that if any ac in the midle of the two resistors, is considered error and compensated on the cathode current. You may use NFb or just ground the second grid. NO -V requiered. Regards. Nafty OBS: 3.6, are Kilos. |
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#10 | |
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diyAudio Member
Join Date: Apr 2004
Location: Philly
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Quote:
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