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#1 |
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diyAudio Member
Join Date: Oct 2003
Location: Upstate New York
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Hello all,
I have been re-reading an article in the April 2004 issue of Audio Express titles "Easy-to-Build, Low-Cost SE Amp". The subject of the article uses 12L6 output tubes to yield about 3.5 watts. In researching these tubes, the output power is stated for a 4000 ohm load. I assume that the 4000 ohm load would be the impedance of the output transformer primary. If I was to parallel a second output tube in order to obtain more power, would I need to halve the transformer primary impedance? Thank you. Mike L. |
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#2 |
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diyAudio Moderator Emeritus
Join Date: Jun 2002
Location: U.K.
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If the 4000 ohms is between 1/3 and 1/2 of the tubes Rp then that's what you want.
Parallelled tubes ideally need to see 1/n of single tube impedance. Eg 1/2 for 2 tubes. John |
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#3 |
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diyAudio Member
Join Date: Nov 2004
Location: Vancouver
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According to RCA's data sheet, the 6L6 could use 4.5K as the plate load for SE class A operation.
JOHnny |
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#4 |
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diyAudio Member
Join Date: Feb 2005
Location: leeuwarden, netherlands
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hello,
I've been to an audio-show and it gave me some stuff to think about. There was an philosophy about getting rid of the d.c. in SE output transformers..... This is done by putting a coil in the anode line....At the output of the tube you place a capacitor that goes to the output-transformer.... Now you don't have the dc in the outputtransformer... (in depth info will be available on www.mennovanderveen.nl) Will this sound nice??? i think so, what are your ideas about this????
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emission over emittor |
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#5 | |
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diyAudio Member
Join Date: Sep 2003
Location: Midland, Michigan
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Quote:
Be aware that the 12L6 is not the same tube as the 6L6. It's a 50L6 with a 12 volt filament.
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Frank |
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#6 | |
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diyAudio Member
Join Date: Jul 2004
Location: Melbourne, Victoria
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Quote:
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Jason |
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#7 | |
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diyAudio Member
Join Date: Jul 2004
Location: Ardeche
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Quote:
Yves |
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