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#1 |
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diyAudio Moderator
Join Date: Mar 2003
Location: diyAudio Special Operations Center
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Hi guys!
I built the circuit below using the part values indicated in the schematic from an old publication. First of all it works, I measure a B+ of 148.8VDC at the plate to ground of the tube and 4.2VDC from cathode to ground (across 22K). Can anyone give me the mathematical formula for computing the gain of this circuit? How do I choose the value of the cathode resistor if I will use different tubes? I would like to learn how to effectively use the graphs in tube datasheets for this particular circuit. Thanks in advance! JojoD PS, I know the supply is a bit low but this is an experiment and I don't want to blow things up especially my tubes. |
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#2 |
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diyAudio Member
Join Date: Feb 2004
Location: South Wales
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Generally speaking, Cathode Followers have no, or a slight reduction in gain, What they do have is the ability to match up a high impedence source to a lower imp load.
If you need gain, you could precede this stage with a common cathode gain stage using the other half of the 6N1p
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Das Beste Oder Nichts |
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#3 | |
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diyAudio Moderator
Join Date: Mar 2003
Location: diyAudio Special Operations Center
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Quote:
But how do I choose the cathode resistor for optimum tube performance? |
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#4 |
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diyAudio Member
Join Date: Mar 2004
Location: 146°E Longitude
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JojoD,
You have to determine first your operating point of the tube you will use. By then, you can compute for the value of cathode resistor. Of course, Ohm's Law will always be here.... |
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#5 | |
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diyAudio Moderator
Join Date: Mar 2003
Location: diyAudio Special Operations Center
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Quote:
Please elaborate. Let's use the 6N1P tube as an example for this exercise. |
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#6 | |
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diyAudio Member
Join Date: Mar 2004
Location: 146°E Longitude
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I don't have datasheet for 6N1P....
But assuming you're using Plate Voltage and Current of 148V and 15mA respectively. Corresponding bias voltage is, say, -6V then you can compute for Rk using this formula:Rk = Vg/Ia Where: Rk = Cathode Resistor Vg = Grid Voltage Ia = Plate Current Please note that above figure is just an assumption, just focus on the above formula base on your operating point that will be used. Tube Gurus, Please correct me if i'm wrong.... Quote:
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#7 |
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diyAudio Moderator
Join Date: Mar 2003
Location: diyAudio Special Operations Center
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I hope this can help us in this exercise...
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#8 |
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diyAudio Member
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Something like this?
Given: 300V on plate bias 15mA 4V / 15mA Rk = 266R Try to search for grounded cathode amplifier at www.tubecad.com. |
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#9 |
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diyAudio Member
Join Date: Mar 2004
Location: 146°E Longitude
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Another one:
Plate Voltage = 200V Plate Current = 10mA Grid Voltage = -2V Rk = 2/0.01 = 200R Hope this help.... |
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#10 | |
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diyAudio Member
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Quote:
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