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I want to make a output transformer of M10
I want to make a output transformer of M10
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Old 13th September 2017, 07:22 PM   #171
pieter t is offline pieter t  Netherlands
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Quote:
Originally Posted by jerrylong View Post
I finished the coil, Prim 4512 turns(0.13mm), Sec 1370 turns(0.13mm, 4 groups parallel connection)
Attachment 634958

Attachment 634960
A bad design
You used about halve the available winding space.
The c-core halves are not tightly kept together by the bands, so there can not be a stable fixed airgap.
Check if the c-core halves are correctly paired; it looks odd.
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Old 14th September 2017, 01:35 AM   #172
jerrylong is offline jerrylong  China
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Winding another coil by hand using the same design for comparison

IMG_5879.JPG

IMG_5884.JPG

IMG_5885.JPG

IMG_5890.JPG
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Old 14th September 2017, 01:36 AM   #173
jerrylong is offline jerrylong  China
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In order to test the conductance and leakage compared with CNC winding one
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Old 22nd September 2017, 05:37 PM   #174
jerrylong is offline jerrylong  China
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Finished the hand winding one

IMG_5939.JPG

And add 0.08 air gap

IMG_5941.JPG
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Old 22nd September 2017, 05:41 PM   #175
jerrylong is offline jerrylong  China
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First test inductance by LCR
Test with 100Hz and 1 volts
IMG_5947.JPG
IMG_5951.JPG
It is about 38H, why that low?
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Old 22nd September 2017, 05:58 PM   #176
jerrylong is offline jerrylong  China
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Second test the leakage
IMG_5952.JPG
It is 73.5mH
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Old 22nd September 2017, 06:07 PM   #177
jazbo8 is offline jazbo8
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I want to make a output transformer of M10
Read post #166.
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Old 22nd September 2017, 08:53 PM   #178
50AE is offline 50AE  Bulgaria
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I want to make a output transformer of M10
73.5mH is a huge amount of leakage. Do you trust this LCR meter?

A not entirely, but more realistic method of measuring parasitic parameters is to short the secondary, then add a capacitor with a small (10-20nF) value shunting the primary. Then measure the first resonant frequency across the primary. Then measure it again without the capacitor. The later should be the default first resonance and higher than the one with the shunt capacitor

The added capacitor is practically in parallel with the Cp (shunt capacitance), so the resonant frequency will be lowered. To find Cp:

Cp = Cadd / [(Fres1/Fres2)^2 - 1]

Fres1 is the frequency without Cadd
Fres2 is the frequency with Cadd
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Old 23rd September 2017, 02:40 AM   #179
jerrylong is offline jerrylong  China
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What Cadd is meaning?
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Old 23rd September 2017, 06:09 AM   #180
jazbo8 is offline jazbo8
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I want to make a output transformer of M10
Cadd = added capacitor.
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