Output impedence in spice

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I'm just sorry that I can not get/simulate good LC PSU with out impedance less than 400 ohms :)

Hmmm....Hmmm... I don't understand....
 

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Rajko, the ringing is now irrelevant, the question was the output impedance.

At 50Hz the last 47uF capacitor impedance is 67.7R (Z=1/2*pi*f*C)
Everything else impedance is parallel this, ergo reduce it.
 

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My calculations for Zout:
Look at the results from PSUD2. When I load increases 5mA, the voltage drop is 2.5V.
d (U)/d (I) = 2.5 / 0.005 = 500 ohms @ 50Hz.

This is my calculations and I believe in it.

I think your calculation is for the voltage drop after having turned on a 5 mA step load? in which case your 500 ohm result is essentially the DC output resistance, not the output impedance at 50 Hz.

Chris
 
Yeah, if you sim it in AC mode, then the simulator computes a linear equivalent of the circuit. If the operating point calculation has the rectifying diodes turned off, then they will be off for the whole calculation, even at 1 Hz. This is of course not realistic, as we would expect the rectifier to impose a voltage on the caps, and therefore a rather low impedance, as the test frequency drops.
 
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