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Old 30th March 2014, 11:47 PM   #1
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Default Troublesome bias resistor, cathodyne stage

I'm working with 50k load resistors on a cathodyne stage, driving a push pull amp. The B+ is 265v, so I need voltage of B+/5 = say 55v at the cathode.

However, despite trying resistances from 1k through to 10k for the bias resistor, I can't vary the voltage from 78v. I've attached the circuit, and the resistor causing this problem is shown in red.

Is anyone able to suggest how I might be able to reduce the voltage to get maximum swing driving the output tubes?
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Old 30th March 2014, 11:57 PM   #2
maton00 is offline maton00  Mexico
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maybe your 0.1uF cap (previous stage) is leaking
also you may try without the 100uf cap
Also you may try cheating with a fixed voltage with a simple voltage divider right in the grid of the phase splitter

Last edited by maton00; 31st March 2014 at 12:14 AM.
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Old 31st March 2014, 12:22 AM   #3
DUG is offline DUG  Canada
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Quote:
Originally Posted by maton00 View Post

...
Also you may try cheating with a fixed voltage with a simple voltage divider right in the grid of the phase splitter
At about 70V.
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Old 31st March 2014, 01:15 AM   #4
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How would this look on the circuit diagram - presumably I'd wire a resistor from one point to another? What would then happen to the bias resistor, etc, could it be removed?
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Old 31st March 2014, 01:30 AM   #5
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Old 31st March 2014, 01:36 AM   #6
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Quote:
Originally Posted by maton00 View Post
also you may try without the 100uf cap
By the way - what is the polarity arrangement of this capacitor. I've got the -ve side facing the 50k resistor, is this correct?
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Old 31st March 2014, 02:27 AM   #7
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Tom,
The capacitor polarity is right.
Another thought ---
Check you have the 470K grid resistor tied to the right end of the 3K3. It is the grid to cathode voltage which sets tube current and therefore will set the cathode voltage.
If the 470K is tied to the cathode side of the bias resistor by mistake that would account for no change of cathode voltage with the changed bias resistor.
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Ian
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Old 31st March 2014, 03:06 AM   #8
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Originally Posted by gingertube View Post
If the 470K is tied to the cathode side of the bias resistor by mistake that would account for no change of cathode voltage with the changed bias resistor.
Interesting - the stage is behaving as if this is how I have it wired, but I definitely think I have it wired correctly.

Here's a picture - the red dot is the junction of where the 470k (running along the outside of the yellow 0.1uF capacitor) meets the bias resistor (which is underneath the small blue capacitor), and also where the 50k load resistor is soldered.

Does it appear to be wired correctly?
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Old 31st March 2014, 11:36 AM   #9
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I took out the 100uf capacitor as some have suggested here, and the cathode voltage is still 78v. Something odd though, is that I can't measure the resistance of the bias resistor. I put the multimeter across the 3k3 resistor (tested on both channels with and without the 100uf capacitor in parallel) and there's no resistance at all. What does that suggest?
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Old 31st March 2014, 01:10 PM   #10
DF96 is offline DF96  England
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It suggests that both ends of the resistor are connected to the same circuit node. This also explains your circuit behaviour. Keep checking your wiring and challenging your assumptions until you find the mistake.
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