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Vacuum Tube SPICE Models
Vacuum Tube SPICE Models
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Old 13th July 2014, 04:54 PM   #511
Ray Waters is offline Ray Waters  United States
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Quote:
Originally Posted by jazbo8 View Post
Sorry to sound like a broken record, but the screen current is poorly modeled using the Koren method. It could be improved, please refer to Dr. Gurskii's article in AA (just a bit better) or Dr. Reefman's improved methodology (great improvement), which requires the uTracer to really take advantage of it.
Do you know if anyone has developed a library of models for some of the common pentodes using the Reefman method? I've been using the Ayumi models because, as you note, the Koren method does not model screen current well, but I'm always on the lookout for something better.
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Old 13th July 2014, 05:08 PM   #512
jazbo8 is offline jazbo8
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Vacuum Tube SPICE Models
Default Reefman SPICE Models

I believe Kevin posted it earlier... if not, yes, Dr. Reefman has kindly provided some models using his improved Koren models here.
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Old 13th July 2014, 05:19 PM   #513
Ray Waters is offline Ray Waters  United States
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Quote:
Originally Posted by jazbo8 View Post
I believe Kevin posted it earlier... if not, yes, Dr. Reefman has kindly provided some models using his improved Koren models here.
Thanks! I'll give these a try.
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Old 13th July 2014, 05:22 PM   #514
RajkoM is offline RajkoM  Bosnia and Herzegovina
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Jazbo8,
by this method, EF80_pentode and EF_triode have identical models.
In practice, I have not encountered such a pentode.


************************************************** **
.SUBCKT EF80 1 2 3 4 ; A G2 G1 C;
* ExtractModel V .997
* Model created: 07-Dec-13
X1 1 2 3 4 PenthodeDE MU= 54.7 EX=1.202 kG1= 136.4 KP= 340.3 kVB = 4670.0 kG2= 584.2
+ Ookg1mOokG2=.56E-02 Aokg1=.23E-05 alkg1palskg2=.56E-02 be= .054 als= 3.09 RGI=2000
+ CCG1=7.5P CCG2=5.4P CPG1 = 0.007p CG1G2 = 2.6p CCP=0.012P ;
.ENDS
************************************************** **
.SUBCKT EF80_triode 1 2 3; A G C;
* ExtractModel V .997
* Model created: 07-Dec-13
X1 1 2 3 TriodeK MU= 54.7 EX=1.202 KG1= 136.4 KP= 340.3 KVB= 4670. RGI=2000
+ CCG=7.5P CGP=2.6P CCP=0.0P ;
.ENDS
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Old 13th July 2014, 05:53 PM   #515
jazbo8 is offline jazbo8
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Quote:
Originally Posted by RajkoM View Post
Jazbo8,
by this method, EF80_pentode and EF_triode have identical models.
In practice, I have not encountered such a pentode.
You are right, they do look odd, but I have no experience with this particular tube. The triode curve seems to deviate quite a bit from an example I found on the net. May be someone with EF80 can verify the results.

Click the image to open in full size.
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Old 14th July 2014, 01:21 AM   #516
needtubes is offline needtubes  United States
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Is there any reason why the triode models would fail to work in inverted triode circuits? The generic TRIODENH model works fine, but my specific tube models fail miserably.
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Old 14th July 2014, 02:41 AM   #517
kevinkr is offline kevinkr  United States
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Vacuum Tube SPICE Models
Modeling grid current? And how the various dependent sources are configured in some models?
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Old 15th July 2014, 10:04 AM   #518
RajkoM is offline RajkoM  Bosnia and Herzegovina
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Default EF50 model

Hi jazbo8.
Can you make EF50 pentode model using Ayumis method, please.
I have several of these tubes, it may be possible to do with them for audio.

Triode curves I borrowed from the net.
Thanks.
Attached Images
File Type: jpg EF50.jpg (214.3 KB, 186 views)
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Old 15th July 2014, 11:51 AM   #519
jazbo8 is offline jazbo8
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Vacuum Tube SPICE Models
Default EF50 Pentode SPICE Model

Please try this one, it's not quite perfect, but should get you started...

Code:
*
* Generic pentode model: EF50_AN
* Copyright 2003--2008 by Ayumi Nakabayashi, All rights reserved.
* Version 3.10, Generated on Tue Jul 15 13:48:26 2014
*               Plate
*               | Screen Grid
*               | |  Control Grid
*               | |  |  Cathode
*               | |  |  |
.SUBCKT EF50_AN A G2 G1 K
BGG   GG   0 V=V(G1,K)+0.075140135
BM1   M1   0 V=(0.016755255*(URAMP(V(G2,K))+1e-10))^-1.7905817
BM2   M2   0 V=(0.45584646*(URAMP(V(GG)+URAMP(V(G2,K))/32.476589)))^3.2905817
BP    P    0 V=0.0062465593*(URAMP(V(GG)+URAMP(V(G2,K))/71.244579))^1.5
BIK   IK   0 V=U(V(GG))*V(P)+(1-U(V(GG)))*0.008577125*V(M1)*V(M2)
BIG   IG   0 V=0.0031232796*URAMP(V(G1,K))^1.5*(URAMP(V(G1,K))/(URAMP(V(A,K))+URAMP(V(G1,K)))*1.2+0.4)
BIK2  IK2  0 V=V(IK,IG)*(1-0.4*(EXP(-URAMP(V(A,K))/URAMP(V(G2,K))*15)-EXP(-15)))
BIG2T IG2T 0 V=V(IK2)*(0.62975016*(1-URAMP(V(A,K))/(URAMP(V(A,K))+10))^1.5+0.37024984)
BIK3  IK3  0 V=V(IK2)*(URAMP(V(A,K))+11000)/(URAMP(V(G2,K))+11000)
BIK4  IK4  0 V=V(IK3)-URAMP(V(IK3)-(0.0032552566*(URAMP(V(A,K))+URAMP(URAMP(V(G2,K))-URAMP(V(A,K))))^1.5))
BIP   IP   0 V=URAMP(V(IK4,IG2T)-URAMP(V(IK4,IG2T)-(0.0032552566*URAMP(V(A,K))^1.5)))
BIAK  A    K I=V(IP)+1e-10*V(A,K)
BIG2  G2   K I=URAMP(V(IK4,IP))
BIGK  G1   K I=V(IG)
* CAPS
CGA   G1  A  0.003p
CGK   G1  K  6p
C12   G1  G2 4p
CAK   A   K  5.3p
.ENDS
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Old 15th July 2014, 02:18 PM   #520
RajkoM is offline RajkoM  Bosnia and Herzegovina
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Thankyou
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