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Old 31st August 2013, 02:59 PM   #1
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Default Russian to English Translation needed

Can someone tell me what it says (translated to English) under the chart on the top right of this datasheet. It looks like current in milliamps is on the vertical axis, but I can't tell what is on the horizontal axis. Ua doesn't look like voltage. There's some writing below the chart that I'd like to know what it says.

Its over here, too.
http://klausmobile.narod.ru/td/data/_6h7b.GIF

http://www.klausmobile.narod.ru/td/l...nverters%20etc
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Last edited by 7n7is; 31st August 2013 at 03:01 PM.
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Old 31st August 2013, 03:04 PM   #2
Mooly is offline Mooly  United Kingdom
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This type of problem has cropped up before. You could try scanning the document with OCR (optical character recognition software such as Abbyy that is often included with printers/scanners) and then copy and paste the text into google/bing translate.
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Old 31st August 2013, 03:08 PM   #3
avp1 is offline avp1  United States
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Quote:
Originally Posted by 7n7is View Post
Can someone tell me what it says (translated to English) under the chart on the top right of this datasheet. It looks like current in milliamps is on the vertical axis, but I can't tell what is on the horizontal axis. Ua doesn't look like voltage. There's some writing below the chart that I'd like to know what it says.

Its over here, too.
http://klausmobile.narod.ru/td/data/_6h7b.GIF

http://www.klausmobile.narod.ru/td/l...nverters%20etc

It is plate voltage. Graph shows plate current vs. voltage around (+ and -) 0 volts.
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Old 31st August 2013, 03:24 PM   #4
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This is a detector diode, so yes, it's Ua (U stands for "Ursache" in German, or cause) which indeed is plate ("Anod") voltage.
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Old 31st August 2013, 03:41 PM   #5
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Right, and the anode voltage has been measured with a 40 K anode load resistor. (сопротивлений наргузки 40 ком)
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Last edited by Blaireau; 31st August 2013 at 03:44 PM.
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Old 31st August 2013, 05:28 PM   #6
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I was wondering why there's current when the voltage is zero. Theoretically, when voltage is zero, current should be zero.
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Old 31st August 2013, 06:10 PM   #7
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It's a detector diode designed for "miniature equipment".

The graph is (as already noted) current vs voltage.

The graph is labelled "the average initial anode characteristic", ie typical performance when new.
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Old 31st August 2013, 06:52 PM   #8
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Does Cyrillic work here?

усредненная - averaged
начальная - primary/initial
анодная - anodic
характеристика - characterization
при - at
сопротивлении - resistance
нагрузки - load
40 ком - 40 Kohm (assuming ком means Kohm)

(using Google Translation and Russian Keyboard OnLine with Spell Check (On-Screen Cyrillic Virtual Keyboard) for typing Cyrillic characters)
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Old 31st August 2013, 09:50 PM   #9
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Originally Posted by 7n7is View Post
I was wondering why there's current when the voltage is zero. Theoretically, when voltage is zero, current should be zero.
Theoretically. However, in practice, electrons don't leave the cathode with zero velocity. Electrons that leave with an initial velocity will still hit the anode even when the Vpk is zero, or even slightly negative. It's similar (but not identical) to the reverse leakage current through a reverse biased SS diode.
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Old 2nd September 2013, 12:14 AM   #10
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If you look at the first graph on the third page here
http://www.wdv.com/Electronics/Radio...d/pdf/6AL5.pdf
you can see that plate current is zero when voltage is zero (on the graph)

I'm wondering how the 6H7b would work in place of a 6AL5 in a ratio detector, for example. I have a couple 6H7b tubes and two 7 pin minature tube sockets which can be soldered to a 6H7b tube and used as a replacement for a 6AL5. Another idea I'm interested in trying is replacing the solid state diodes in a Pilot 100 stereo demodulator with vacuum tube diodes to see if the distortion is lower with tube diodes. Vacuum tube diodes are foward biased at a lower voltage compared to solid state diodes (about 0.3 volts for Ge and 0.6 volts for Si).
http://members.shaw.ca/pacifictv5/pilot100.jpg

Last edited by 7n7is; 2nd September 2013 at 12:18 AM.
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