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Old 21st November 2011, 09:13 AM   #1
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Default Effective cathode resistance

Reading through Morgan Jones' 'Valve Amplifiers', in the section on selecting a cathode by-pass capacitor, MJ states that the effective resistance looking in at the cathode is: (ra + RL)/(u + 1) in parallel with the cathode bias resistor (p79, Third Edition).

Can anyone point me to the derivation of the (ra + RL)/(u + 1) part?

Many thanks.

ac
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Old 21st November 2011, 10:05 AM   #2
DF96 is offline DF96  England
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Any good book on valve circuit theory should include it. It may be presented as the input impedance of the grounded grid amplifier.

A rough-and-ready way to understand it goes something like this:
The valve acts like a resistance ra, which is in series with the anode load RL, so you get ra+RL. However, when looking from the cathode (with a fixed grid potential) the amplification of the valve greatly increases the current flow for a small change in voltage so instead of ra+RL you get (ra+RL)/u. An exact calculation gives u+1 instead of u.
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